Which process is based on repulsion of oil and water?

Chemistry

2 answers:

Inessa [10]3 years ago

5 0

Answer:

We can seprate oil and water by the process of seprating funnel

34kurt3 years ago

4 0

Lithoghraphy
Lithoghraphy is a process based on the repulsion of oil and water. An image that is offset printed is separated into its fundamental colors.

You might be interested in

Which type of equilibrium exists in a sealed flask containing Br2(ℓ) and Br2(g) at 298 K and 1.0 atm?(1) static phase equilibriu

marishachu [46]

The correct answer is 3.

A dynamic phase equilibrium is when a reversible reaction no longer changes its ratio of reactants to products. However, substances continue to move between the chemicals at an equal rate, which means the net change is 0. This is known as a steady state.

8 0

4 years ago

1. A sample of polystyrene is found to have a number-average molar mass of 89,440 g mol−1 . Neglecting contributions from end gr

Snowcat [4.5K]

Answer:

The weight-average molar mass of polystyrene is 134,160 g/mol.

Explanation:

Molar mass of the monomer styrene , $C_8H_8$ , M=104 g/mol

Given , number average molar mass of the polymer , M'= 89,440 g/mol

Degree of polymerization = n

$n=\frac{M'}{M}=\frac{89,440 g/mol}{104 g/mol}=860$

The weight-average molar mass = $M_{avg}=?$

Molar mass dispersity is ratio of weight-average molar mass to the number average molar mass of the polymer.

$\text{Molar mass dispersity}=\frac{M_{avg}}{M'}$

$1.5=\frac{M_{avg}}{89,440 g/mol}$

$M_{avg}=89,440 g/mol\times 1.5 = 134,160 g/mol$

The weight-average molar mass of polystyrene is 134,160 g/mol.

8 0

3 years ago

Which formula can be used to find velocity if kinetic energy and mass are known?

astraxan [27]

Answer:

$v = \sqrt{ \frac{2ke}{m} }$

option D is the correct option.

Here,

If an object of mass 'm' moving with a velocity'v' then,

$kinetic \: energy = \frac{1}{2} m {v}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {v}^{2} = \frac{2ke}{m} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {v}^{2} = \sqrt{ \frac{2ke}{m} }$