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liberstina [14]
3 years ago
10

If the p-side has a higher doping concentration, explain how to keep tuning to the same radio channel?

Chemistry
1 answer:
zzz [600]3 years ago
6 0

Answer:

increase in temperature of the intrinsic semiconductor

Explanation:

  • If the p-side has a higher doping concentration, it implies that number of holes (positive ion) increased which is greater than number of electron (negative ion) in the n-side
  • in order to balance the intrinsic concentration, that is to balance the number of holes and electrons which depends on temperature.
  • an increase in the temperature of the intrinsic semiconductor (p-side), increases the number of electron but number of holes remains constant.

A balance in the intrinsic concentration helps in tuning to the same radio channel.

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Redox titrations are used to determine the amounts of oxidizing and reducing agents in solution. For example, a solution of hydr
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Answer:

0.374 g

Explanation:

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Since both the molarity and the volume allows us to know the moles of potassium permanganate, and we already have the balanced chemical reaction, the stoichiometric procedure that is attached in the picture, is developed to substantiate the the titrated mass of hydrogen peroxide was 0.374 g.

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3 years ago
What is the molar mass of magnesium
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3 years ago
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2 years ago
Driving cars lowers the pH of the oceans by _______.
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if three oxygen particles are needed to form ozone, how many units of ozone could be formed from 6 oxygen particles? from 9? fro
tensa zangetsu [6.8K]
<h3>Answers:</h3>

             1) 2 Units of Ozone

             2)  3 Units of Ozone

              3)  9 Units of Ozone

<h3>Solution:</h3>

1)  From 6 Oxygen Particles;

As given,

                          3 Oxygen Particles form  =  1 Unit of Ozone

So,

                      6 Oxygen Particles will form  =  X Units of Ozone

Solving for X,

                      X =  (6 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

                      X =  2 Units of Ozone

2) From 9 Oxygen Particles;

As given,

                           3 Oxygen Particles form  =  1 Unit of Ozone

So,

                      9 Oxygen Particles will form  =  X Units of Ozone

Solving for X,

                      X =  (9 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

                      X =  3 Units of Ozone

3)  From 27 Oxygen Particles;

As given,

                             3 Oxygen Particles form  =  1 Unit of Ozone

So,

                      27 Oxygen Particles will form  =  X Units of Ozone

Solving for X,

                      X =  (27 O Particles × 1 Unit of Ozone) ÷ 3 O Particles

                      X =  9 Units of Ozone

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3 years ago
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