All categories

3 years ago

This element is less reactive than lithium and magnesium but more reactive than zinc. Which element is this?

Chemistry

2 answers:

Leni [432]3 years ago

8 0

I searched online since i felt bad it is B

Tamiku [17]3 years ago

7 0

The answer should be:

B. Al (Aluminium)

You might be interested in

Which of the following statements is true about the relationships between photon energy, wavelength, and frequency?

iris [78.8K]

Answer: The Answer is A.

Explanation:

The amount of energy is directly proportional to the photon's electromagnetic frequency and thus, equivalently, is inversely proportional to the wavelength. The higher the photon's frequency, the higher its energy. Equivalently, the longer the photon's wavelength, the lower its energy.

Hope this Helps!

8 0

3 years ago

List an example of earth landforms changing due to weathering and erosion

Helga [31]

Answer:

i believe the grand canyon is an example

Explanation:

4 0

3 years ago

The combustion of 0.590 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera

Alenkinab [10]

Answer:

2.943 °C temperature change from the combustion of the glucose has been taken place.

Explanation:

Heat released on combustion of Benzoic acid; :

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.590 g

Moles of benzoic acid = $\frac{0.590 g}{122.12 g/mol}=0.004831 mol$

Energy released by 0.004831 moles of benzoic acid on combustion:

$Q=3,228 kJ/mol \times 0.004831 mol=15.5955 kJ=15,595.5 J$

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.125°C

$Q=C\times \Delta T$

$15,595.5 J=C\times 2.125^oC$

$C=7,339.05 J/^oC$

Heat released on combustion of Glucose: :

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=1.400 g

Moles of glucose = $\frac{1.400 g}{180.16 g/mol}=0.007771 mol$

Energy released by the 0.007771 moles of calorimeter combustion:

$Q'=2,780 kJ/mol \times 0.007771 mol=21.6030 kJ=21,603.01 J$

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

$Q'=C\times \Delta T'$

$21,603.01 J=7,339.05 J/^oC\times \Delta T'$

$\Delta T'=2.943^oC$

2.943 °C temperature change from the combustion of the glucose has been taken place.

8 0

3 years ago

20 POINTS!!

Andrews [41]

Answer:

B. Interferon

Explanation:

interferon targets any lingering melanoma cells and prevents them from spreading and growing.

3 0

3 years ago

A force of 2,500 pounds drags a truck 30 feet in 1/2 minute.

scoray [572]

The right subject for this question is physics.

To calculate the work you use the formula:

Work = force * displacement

Work = 2500 pounds * 30 feet = 75,000 pounds - feet

To calculate the power you use the formula:

power = work / time

Power = 75,000 pound - feet / 30 seconds = 2300 pound-feet / second.

3 0

3 years ago