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Jlenok [28]
3 years ago
9

A circuit constrains one light bulb and one battery. What happens to the total resistance in the circuit if you replace one ligh

t bulb with a string of four identical bulbs?Why?
Physics
1 answer:
iogann1982 [59]3 years ago
4 0

-- If the four light bulbs are in <u><em>series</em></u>, then the total resistance becomes <em>four times as much</em> as it was with a single bulb, because now, the current has to push through one light bulb four times.

-- If the four light bulbs are in <u><em>parallel</em></u>, then the total resistance becomes <em>1/4 as much</em> as it was with a single bulb, because now, the current can split up into four equal streams, and each stream only has to push through a single light bulb.  

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The Moon and Earth rotate about their common center of mass, which is located about 4700 km from the center of Earth. (This is 1
Nesterboy [21]

Answer:

a) a_c=3.41x10^{-5} \frac{m}{s^2}

b) a_c=3.34x10^{-5}\frac{m}{s^2}  

If we analyze the two values obtained for the centripetal acceleration we see that are similar. Based on this we can say that the centripetal force would be similar to the gravitational force between the Earth and Moon.

Explanation:

1) Notation and important concepts

Centripetal acceleration is defined as "The acceleration experienced while in uniform circular motion. It always points toward the center of rotation and is perpendicular to the linear velocity."

Angular frequency is defined as "(ω), or radial frequency, measures angular displacement per unit time and the units are usually degrees (or radians) per second. "

T = 27.3 d represent the time required by the Earth around an specific point given in the problem

G= universal constant 6.673x10^{-11}\frac{Nm^2}{kg^2}

M= represent the mass of the Moon=7.35x10^{22}kg

2) Part a

a=\frac{GM}{r^2}   (1)

The Earth-Moon Distance Is 3.84x10^8 km (average Value) and both rotates at a point located about 4700 km from the center of Earth, so the radius for this case would be the difference between these two values

r=(3.84x10^8 km)-(4.7x10^6)=3.793x10^8 m

Since we have the radius now we can replace into equation (1)

a=\frac{(6.673x10^{-11}\frac{Nm^2}{kg^2})(7.35x10^22 kg)}{(3.793x10^8 m)^2}=3.41x10^{-5} \frac{m}{s^2}

And the acceleration due to the Moon's gravity would be 3.41x10^{-5} \frac{m}{s^2} at the point required.

3)Part b

For this case we can find the centripetal acceleration from this formula:

a_c =r \omega^2   (2)

But on this case we don't have the angular frequency so we can find it with this formula

\omega =\frac{2\pi}{T}   (3)

But since the period is on days we need to convert that into seconds

27.3dx\frac{86400s}{1d}=2358720sec

Replacing the value into equation (3) we got:

\omega =\frac{2\pi}{2358720}=2.664x10^{-6}\frac{rad}{s}  

Now we can find the centripetal acceleration with the equation (2), the new radius on this case since our reference is the Earth and the point is located 4700km=4700000m from the center of Earth then the new value for the radius would be r=4700000m

a_c =r \omega^2 =(4700000m)(2.664x10^{-6}\frac{rad}{s})^2=3.34x10^{-5}\frac{m}{s^2}  

If we analyze the two values obtained for the centripetal acceleration we see that are similar. Based on this we can say that the centripetal force would be similar to the gravitational force between the Earth and Moon.

5 0
3 years ago
What happens along a stationary front?
oee [108]

Answer: b. The flow of air is neither toward the warm air mass nor toward the cold air mass.

A stationary front forms between two air masses. A stationary front results when the warm front or cold front air stops moving. This occurs due to the fact that warm front and cold front air masses being opposite to each other but neither of them are able to repel the other. This affects the climatic conditions of the region. The weather is often cloudy along a stationary front and also supported with fall of rain and snow especially if the air in the front is cold with low atmospheric pressure.

<em>Therefore, along a stationary front the flow of air is neither toward the warm air mass nor toward the cold air mass. </em>



3 0
3 years ago
What does resonance result in?
marin [14]
“The vibrations of the aluminum force the air Column inside of the rod to vibrate at its natural frequency. The match between the vibrations of the air column and one of the natural frequencies of the singing rod causes resonance.”
3 0
3 years ago
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A copper wire is stretched so that its length increases and its diameter decreases. what is the result?
Dovator [93]

The result is although the wire's resistivity doesn't change, its resistance does.

Considering the formula for a material's resistance:

​R=pL/A

R is directly proportional to L and inversely proportional to A, as can be seen. Be aware that "rho" is a material-specific and intensive attribute (meaning this value will not change if the material is only physically altered). Remember that A = This implies that the relationship between R and the square of r is inverse. When the wire is stretched, the impacts on length are less noticeable than the effects on r. Therefore the wire's resistance increases, but its resistivity stays the same.

Learn more about resistance here:

brainly.com/question/20708652

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2 years ago
An eagle that has a mass of 4.5 kg is spotted 5 m above a lake. It flies up to its nest in a tree at a height of 25 m. How much
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The eagle gained 882 J of gravitational potential energy.
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3 years ago
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