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Jlenok [28]
3 years ago
9

A circuit constrains one light bulb and one battery. What happens to the total resistance in the circuit if you replace one ligh

t bulb with a string of four identical bulbs?Why?
Physics
1 answer:
iogann1982 [59]3 years ago
4 0

-- If the four light bulbs are in <u><em>series</em></u>, then the total resistance becomes <em>four times as much</em> as it was with a single bulb, because now, the current has to push through one light bulb four times.

-- If the four light bulbs are in <u><em>parallel</em></u>, then the total resistance becomes <em>1/4 as much</em> as it was with a single bulb, because now, the current can split up into four equal streams, and each stream only has to push through a single light bulb.  

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Answer:

Given:

Fundamental frequency: 470Hz

T1:310k,T2:315k

Calculating velocity

Recall v=(331m/s)✓[T1/273k)

V=331✓(310/273)

V1=331*(1.0656)=352.72m/s

V2=331✓(315/273)=355.5m/s

Fundamental frequency=4L

F2=F1(V2/V1)

F2=470(355.5/352.72)=474.4Hz

Beat=[F2-F1]=474.4-470=4.4Hz

Explanation:

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Given the information below, estimate the total distance travelled during these 6 seconds using a left endpoint approximation. t
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Answer:

184 feets

Explanation:

Given the data:

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0 __________30

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2 __________56

3 __________34

4 __________ 8

5 __________ 2

6 __________22

Using left end approximation:

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