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almond37 [142]
3 years ago
15

What is the least common denominator (LCD) of 1/2 and 2/3 ?

Mathematics
2 answers:
MrRissso [65]3 years ago
8 0
So basically you just want to find the LCM of the denominators shown, or 2 and 3. 

So in this case, you could use the most inefficient method, or listing the multiples out:

2 : 2, 4, 6

3: 3, 6, 9

And as you can see, the first multiple that matches is 6. So your answer would be B, 6.
kherson [118]3 years ago
6 0

Answer:

B(6

Step-by-step explanation:

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Please help 2х -3y =18
siniylev [52]

Answer:

x = 3(6 + y)/2

Step-by-step explanation:

Solving for x

Add 3y to both sides.

2x = 18 + 3y

Divide both sides by 2.

x = 18 + 3y/2

Factor out the common term 3.

x = 3(6 + y)/2

3 0
3 years ago
Help I'm really confused. i need this ASAP!!!!!<br> -9a^2b^6(-7ab^-4)
Eva8 [605]
The top of “^” needs a number to solve it.
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3 years ago
Tan^2 A/1+cot^2 A + cot^2 A/1+tan^2 A=sec^2 A cosec^2 A-3
omeli [17]
\frac{tan^2x}{1+cot^2x}+\frac{cot^2x}{1+tan^2x}=sec^2x\ cosec^2x-3\\\\L=\frac{tan^2x(1+tan^2x)+cot^2x(1+cot^2x)}{(1+cot^2x)(1+tan^2x)}=\frac{tan^2x+tan^4x+cot^2x+cot^4x}{1+tan^2x+cot^2x+tanxcotx}\\\\=\frac{tan^2x+cot^2x+tan^4x+cot^4x}{1+tan^2x+cot^2x+1}=\frac{tan^2x+2+cot^2x+tan^4x-2+cot^4x}{tan^2x+cot^2x+2}

=\frac{(tanx+cotx)^2+(tan^2x-cot^2x)^2}{(tanx+cotx)^2}=\frac{(tanx+cotx)^2}{(tanx+cotx)^2}+\frac{(tan^2x-cot^2x)^2}{(tanx+cotx)^2}\\\\=1+\frac{(tanx-cotx)^2(tanx+cotx)^2}{(tanx+cotx)^2}=1+(tanx-cotx)^2\\\\=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\\\\=\left(\frac{sinx}{cosx}\right)^2+\left(\frac{cosx}{sinx}\right)^2-1=\frac{sin^2x}{cos^2x}+\frac{cos^2x}{sin^2x}-1=\frac{sin^4x+cos^4x}{sin^2x\ cos^2x}-1

=\frac{(sin^2x)^2+2sin^2x\ cos^2x+(cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{(sin^2x+cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{1}{sin^2x\ cos^2x}-\frac{2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1}{sin^2x}\cdot\frac{1}{cos^2x}-2-1\\\\=cosec^2x\cdot sec^2x-3=sec^2x\ cosec^2x-3=R
3 0
3 years ago
Find the volume of a cylinder with a diameter of 16 mm and a height of 5.7 mm
Mademuasel [1]
The volume formula for a cylinder is :
V= (pi)(r^2)(h)
So r= d/2 where d = 16mm so r= 8mm h is given as equaling 5.7mm
Now just plug it into the formula.
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3 0
3 years ago
3/4 divided by 5 1/5 =
anyanavicka [17]
0.1442
0.1714
0.05487
0.2075
5 0
3 years ago
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