it sinks into the liquid
(e.g. water sinks under oil as it is more dense)
The actual mass of a 1 cm² piece of copy paper is determined as 0.0074 g.
<h3>Area of the sheet of paper in square centimeters</h3>
Area = Length x Width
Area = (11 x 2.54 cm) x (8.5 x 2.54 cm)
Area = 603.22 cm²
<h3>Actual mass of the sheet of paper</h3>
Mass = area density/area
Mass = (4.5 gcm²)/(603.22 cm²)
Mass = 0.0074 g
The complete question is below:
A sheet of 8.5 inch by 11inch paper has a mass of 4.50 grams one square centimeter , 1cm2 of that sheet of paper will have a mass closets to ____grams ( (hint use 1inch = 2.54 centimeters and area = length times)
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B. picking up a box off the floor
The tensions in the wires at the given angle of inclination is determined as 434.1 N.
<h3>
Tension on the wire</h3>
The tension in the wires is calculated as follows;
T = Wsinθ
where;
- T is tension in each wire
- W is weight of the traffic light
T = 2500 x sin(10)
T = 434.1 N
Thus, the tensions in the wires at the given angle of inclination is determined as 434.1 N.
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Answer:
682.32 m
Explanation:
Speed of the passing speeder = 120 km/hr = 120 × 0.2777 = 33.33 m/s
time after which police man starts = 2 seconds
Acceleration of the policeman = 4.0 m/s²
let the time taken to catch be 't' seconds
Now,
The total distance to be covered by the policeman
= Distance covered by the speeder in the 2 seconds + Distance further traveled by the speeder in time t
thus,
From Newton's equation of motion
where,
s is the total distance traveled by the police man
u is the initial speed = 0
a is the acceleration
t is the time
thus,
= 33.33 × 2 + 33.33 × t
or
2t² = 66.66 + 33.33t
or
2t² - 33.33t - 66.66 = 0
on solving the above equation, we get
t = 18.47 seconds (negative value is ignored as time cannot be negative)
therefore,
the total distance covered = 33.33 × 2 + 33.33 × 18.47 = 682.32 m
