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3 years ago

Which of the following is not an example I work?? Some please help

Physics

2 answers:

n200080 [17]3 years ago

8 0

B. picking up a box off the floor

KengaRu [80]3 years ago

5 0

I would pick raising a barbell over your head...

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Answer:

HERE IS YOUR ANSWER

Explanation:

PLEASE MARK MY ANSWER AS BRAINLIEST IF THE ANSWERS ARE CORRECT .

Beacuse of the loose connection of the wire .

Straight

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3 years ago

Describe a positive and negative net force acting on an object

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3 years ago

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dalvyx [7]

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2 years ago

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A student wants to design an experiment to study the transformation of mechanical energy. Which object can be used to investigat

Vsevolod [243]

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2 years ago

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When a potential difference of 10 V is placed across a certain solid cylindrical resistor, the current through it is 2 A. If the

lord [1]

Answer:

The current will be 18 A

Explanation:

Given;

potential difference, V = 10 V

current between the resistor, I = 2 A

Apply ohm's law;

V = IR

R = V / I

R = 10 / 2

R = 5Ω

Resistance is given as;

$R = \frac{\rho l}{A}$

where;

ρ is resistivity

l is length

A is area

$R = \frac{\rho l}{A} \\\\R = \frac{\rho l}{\pi r^2} = \frac{\rho l}{\pi (\frac{d}{2}) ^2} = \frac{\rho l}{\pi (\frac{d^2}{4}) }\\\\R = \frac{4*\rho l}{\pi d^2} \\\\R = (\frac{4*\rho l}{\pi } )\frac{1}{d^2} \\\\R = (k)\frac{1}{d^2} \\\\k = Rd^2\\\\R_1d_1^2 = R_2d_2^2\\\\R_2 = \frac{R_1d_1^2}{d_2^2}$

When the diameter of the resistor is tripled

d₂ = 3d₁

$R_2 = \frac{5*d_1^2}{(3d_1)^2} \\\\R_2 = \frac{5d_1^2}{9d_1^2} \\\\R_2 = 0.556 \ ohms$

The current is now calculated as;

Apply ohms law;

V = IR

I = V / R

I = 10 / 0.556

I = 17.99 A

I = 18 A

Therefore, the current will be 18 A

4 0

3 years ago