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galina1969 [7]
3 years ago
13

Two cars collide inelastically and stick together after the collision. Before the collision, the magnitudes of their momenta are

P1 and P2 . After the collision, what is the magnitude of their combined momentum?
a) P1+P2
b) P1-P2
c) P2-P1
d) (P1P2)^(1/2)
e) (1/2)(P1+P2)
f) (P1+P2)^(1/2)
Physics
1 answer:
dolphi86 [110]3 years ago
3 0

Answer:

a) P1+P2

Explanation:

The magnitude of their combined momentum is just the addition of each momentum, because in this case of inelastic collision, the kinetic energy of the two cars are both converted to some form of energy because the velocity of both cars becomes zero, i.e., V=0, making P = mv = 0, this means the magnitude of P1 + P2 = 0.

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mice total momentum (-0.000250, 0.00639) Kg m

Explanation:

To calculate the moment of the mice we must multiply their mass by their velocities, remember that the moment is a vector quantity, so we use the components of velocity

mouse 1

  m1 = 0.0225 Kg

  V1 = (0.869, -0.283) m / s

 

  Px = m Vx

  Px1 = 0.0225 0.869

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  Py1 = 0.0225 (-0.283)

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Mouse 2

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 Px2 = 0.0223 (-0.883) = -0.0196 Kg m

 Py2 = 0.0223 (-0.253) = -0.00564 Kg m

 P2 = (-0.0196, -0.00564) Kg m

Mouse 3

 m3 = 0.0197

 Px3 = 0.0197 0.345 = 0.00680 Kg m

 Py3 = 0.0197 0.803 = 0.0158 Kg m

 P3 = (0.00680, 0.0158) Kg m

Mouse4

  m4 = 0.0127 Kg

  Px4 = 0.0127 (-0.555) = -0.00705 Kg m

  Py4 = 0.0127 0.205 = 0.00260 Kg m

  P4 = (-0.00705, 0.00260) Kg m

To find the total momentum we must add each component of the individual moments

   Px = Px1 + Px2 + Px3 + Px4  

   Py = py1 + Py2 + Py3 + Py4

   Px = 0.0196 -0.0196 +0.00680 -0.00705

   Px = -0,000250 Kg m

   Py = -0.00637 -0.00564 +0.0158 +0.00260

   Py = 0.00639 Kg m

   P = (-0.000250, 0.00639) Kg m

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