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galina1969 [7]
3 years ago
13

Two cars collide inelastically and stick together after the collision. Before the collision, the magnitudes of their momenta are

P1 and P2 . After the collision, what is the magnitude of their combined momentum?
a) P1+P2
b) P1-P2
c) P2-P1
d) (P1P2)^(1/2)
e) (1/2)(P1+P2)
f) (P1+P2)^(1/2)
Physics
1 answer:
dolphi86 [110]3 years ago
3 0

Answer:

a) P1+P2

Explanation:

The magnitude of their combined momentum is just the addition of each momentum, because in this case of inelastic collision, the kinetic energy of the two cars are both converted to some form of energy because the velocity of both cars becomes zero, i.e., V=0, making P = mv = 0, this means the magnitude of P1 + P2 = 0.

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A 2500 kg car traveling to the north is slowed down uniformly from an initial velocity of 20 m/s by a 5620 N braking force actin
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the distance traveled by the car is 42.98 m.

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mass of the car, m = 2500 kg

initial velocity of the car, u = 20 m/s

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time of motion of the car, t = 2.5 s

The decelaration of the car is calculated as follows;

-F = ma

a = -F/m

a = -5620 / 2500

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The distance traveled by the car is calculated as follows;

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