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4 years ago

The metric unit of force is _____.

Physics

2 answers:

Amanda [17]4 years ago

6 0

Answer:

The metric unit of force is the Newton (N)

Explanation:

Force is defined as the product between mass and acceleration:

$F=ma$

The mass of an object (m) is measured in kilograms (kg), while the acceleration (a) is measured in meters per squared second (m/s^2). So, the metric unit of the force is

$[F]=[kg] \frac{[m]}{[s^2]}$

This unit is called Newton, its symbol is N, and this is the metric unit of the force.

OlgaM077 [116]4 years ago

3 0

The metric unit is the Newton (N), or the $\frac{kgm}{s^{2} }$

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(A) $4.2\cdot 10^5 J$

The energy stored by the system is given by

$E=Pt$

where

P is the power provided

t is the time elapsed

In this case, we have

P = 60 kW = 60,000 W is the power

t = 7 is the time

Therefore, the energy stored by the system is

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(B) 4830 rad/s

The rotational energy of the wheel is given by

$E=\frac{1}{2}I \omega^2$ (1)

where

$I$ is the moment of inertia

$\omega$ is the angular velocity

The moment of inertia of the wheel is

$I=\frac{1}{2}MR^2=\frac{1}{2}(5 kg)(0.12 m)^2=0.036 kg m^2$

where M is the mass and R the radius of the wheel.

We also know that the energy provided is

$E=4.2\cdot 10^5 J$

So we can rearrange eq.(1) to find the angular velocity:

$\omega=\sqrt{\frac{2E}{I}}=\sqrt{\frac{2(4.2\cdot 10^5 J)}{0.036 kg m^2}}=4830 rad/s$

(C) $2.8\cdot 10^6 m/s^2$

The centripetal acceleration of a point on the edge is given by

$a=\omega^2 R$

where

$\omega=4830 rad/s$ is the angular velocity

R = 0.12 m is the radius of the wheel

Substituting, we find

$a=(4830 rad/s)^2 (0.12 m)=2.8\cdot 10^6 m/s^2$

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4 years ago

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Answer:

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3 years ago

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Whitepunk [10]

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Hope this helps! ;)

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3 years ago

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WITCHER [35]

Answer:

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Explanation:

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You can use photo math for This

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