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xenn [34]
3 years ago
12

I am thinking of creating a LGBTQ+ Brainly page where I offer information, advice, etc. Do you think this is a good idea?

Physics
1 answer:
Igoryamba3 years ago
3 0

Answer:

yes it sounds like a great idea but not on brainly, that is more for fb, tt, and other apps like that. If you tt account on it i'll def follow you just tell me what your account name is.

Explanation:

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A 30kg mass is brought from the earth to the moon what is the weight on the earth
ozzi

Answer:

Solution

verified

Verified by Toppr

Given:

Mass of body = 30 kg

gravitational acceleration on the moon = 1.62 m/s

2

Weight of the body on the moon = Mass of the body×gravitational acceleration on the moon=30×1.62=48 N

8 0
2 years ago
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IrinaK [193]
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3 years ago
On the Moon's surface, lunar astronauts placed a corner reflector, off which a laser beam is periodically reflected. The distanc
Arisa [49]

Answer:

Explanation:

The difference in time will be due to travel through atmosphere where speed of light slows down. If t be the thickness of atmosphere and c be the speed of light in space and μ be the refractive index of atmosphere difference in travel time will be as follows .

difference = \frac{2t\mu }{c}-\frac{2t }{c}

=\frac{2t}{c }\left ( 1-\mu  \right )

Now t = 40 x 10³m ,μ = 1.000293 , c = 3 x 10⁸.

difference =\frac{2t\mu }{c}-\frac{2t }{c}

=\frac{2t}{c }\left ( \mu -1  \right )\\

=\frac{ 2\times 40\times 10^3}{3\times10^3 }\left ( 1.000293-1 \right )\\

=7.81\times 10^{-3} s

4 0
4 years ago
Cardiorespiratory fitness improves the efficiency of the cardiovascular and the respiratory systems in delivering oxygen to the
Sergeeva-Olga [200]

This question is incomplete because the options are not given; here is the complete question:

Cardiorespiratory fitness improves the efficiency of the cardiovascular and the respiratory systems in delivering oxygen to the body.

Please select the best answer from the choices provided.

True

False

The correct answer to this question is True

Explanation:

The cardiorespiratory system (cardiovascular and respiratory system) includes structures and organs such as the heart, the lungs, the veins, etc. that are involved in the process of oxygenation of the body. This process can be less or more efficient depending on different factors. One of these is the cardiorespiratory fitness or the ability of the body to work effectively in terms of oxygenation during exercise or effort.

In this context, a higher cardiorespiratory fitness means the cardiorespiratory system will work more efficiently, while low fitness implies less efficient oxygenation. Additionally, this fitness can be improved through activities such as running, hiking, among others. Therefore, cardiorespiratory fitness improves efficiency in the process of oxygenation, which makes the statement true.

3 0
3 years ago
Read 2 more answers
if the vessel in the sample problem accelerates fir 1.00 min, what will its speed be after that minute ?
LUCKY_DIMON [66]

Answers:

a) 154.08 m/s=554.68 km/h

b) 108 m/s=388.8 km/h

Explanation:

<u>The complete question is written below: </u>

<u></u>

<em>In 1977 off the coast of Australia, the fastest speed by a vessel on the water was achieved. If this vessel were to undergo an average acceleration of 1.80 m/s^{2}, it would go from rest to its top speed in 85.6 s.  </em>

<em>a) What was the speed of the vessel? </em>

<em> </em>

<em>b) If the vessel in the sample problem accelerates for 1.00 min, what will its speed be after that minute? </em>

<em></em>

<em>Calculate the answers in both meters per second and kilometers per hour</em>

<em></em>

a) The average acceleration a_{av} is expressed as:

a_{av}=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{\Delta t} (1)

Where:

a_{av}=1.80 m/s^{2}

\Delta V is the variation of velocity in a given time \Delta t, which is the difference between the final velocity V and the initial velocity V_{o}=0 (because it starts from rest).

\Delta t=85.6 s

Isolating V from (1):

V=a_{av}\Delta t + V_{o} (2)

V=(1.80 m/s^{2})(85.6 s) + 0 m/s (3)

V=154.08 \frac{m}{s} (4)

If 1 km=1000m and 1 h=3600 s then:

V=154.08 \frac{m}{s}=554.68 \frac{km}{h} (4)

b) Now we need to find the final velocity when \Delta t=1 min=60 s:

<em></em>

V=(1.80 m/s^{2})(60 s) + 0 m/s (5)

V=108 \frac{m}{s}=388.8 \frac{km}{h} (6)

5 0
3 years ago
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