Answer:
Given that
u = 13 m/s
h= 23 m
a) horizontally
We know that acceleration due top gravity is in vertical direction.
v²=u'²+ 2 g h ( u'= 0 )
v² = 2 x 9.81 x 23
v= 21.24 m/s ( vertical direction)
In the horizontal direction
u = 13 m/s
The resultant velocity
V²=v²+u²
V²=21.24²+13²
V= 24.91 m/s
(b) vertically straight up
u= 13 m/s
v²=u²+ 2 g h
v²=13²+ 2 x 9.81 x 23
v= 24.91 m./s
c)vertically straight down.
u= 13 m/s
v²=u²+ 2 g h
v²=13²+ 2 x 9.81 x 23
v= 24.91 m./s
the answer is C the wave is moving horizontally as the particles of the rope move up and down.
I think the correct answer would be the last option. On a cloudless day, most of the visible light that is headed towards the Earth would reach the surface wherein some is being reflected and some is being absorbed. During this time, there are no hindrances for the light so it directly reaches the surface of the Earth and is absorbed or reflected by the objects it hits.
Electricity is the controlled flow of electrons. They are made to travel in the same direction at the same time. If you have an insulator, it stops or severely inhibits the flow of electrons. Such a device is found on telephone poles. Those are made of glass like materials.
Answer:
Angular momentum,
Explanation:
It is given that,
Radius of the axle,
Tension acting on the top, T = 3.15 N
Time taken by the string to unwind, t = 0.32 s
We know that the rate of change of angular momentum is equal to the torque acting on the torque. The relation is given by :
Torque acting on the top is given by :
Here, F is the tension acting on it. Torque acting on the top is given by :
So, the angular momentum acquired by the top is . Hence, this is the required solution.