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QveST [7]
3 years ago
6

URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (60pt

s)

Physics
1 answer:
tigry1 [53]3 years ago
5 0

Answer:

Answer:

D) by using military force.

Explanation:

Typically, people like Mussolini and Stalin gain popularity in trying times by promising a type of well-being to a group or nation of stricken people, in which they gain huge amounts of popularity at once. Typically they are then elected to some seat of power, in which, with popularity and most likely the military on their side, they would overthrow the current government. The next step taken is to suppress any opposition or even those who don't fully support the party. This can be given out in two ways, which is through force (especially opposition), or providing benefits to those who are in the party (to draw those who are not exactly supporting to support for the benefits).

With "popular" support, as well as military control, the overthrow is complete, and the group is established in power.

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during the thin layer chromatography non volatile mixtures are separated.The technique is performed on the plastic or aluminum foil that is coated with a thin layer.

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6 0
3 years ago
Read 2 more answers
Assume that the electric field E is equal to zero at a given point. Does it mean that the electric potential V must also be equa
lyudmila [28]

Answer:

  • No, this doesn't mean the electric potential equals zero.

Explanation:

In electrostatics, the electric field \vec{E} is related to the gradient of the electric potential V with :

\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r})

This means that for constant electric potential the electric field must be zero:

V(\vec{r}) = k

\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r}) = - \vec{\nabla} k

\vec{E} (\vec{r}) = -  (\frac{\partial}{\partial x} , \frac{\partial}{\partial y } , \frac{\partial}{\partial z}) k

\vec{E} (\vec{r}) = -  (\frac{\partial k}{\partial x} , \frac{\partial k}{\partial y } , \frac{\partial k}{\partial z})

\vec{E} (\vec{r}) = -  (0,0,0)

This is not the only case in which we would find an zero electric field, as, any scalar field with gradient zero will give an zero electric field. For example:

V(\vec{r})= (x+2)^2 (y+4)^3 (z+5)^4

give an electric field of zero at point (0,0,0)

8 0
3 years ago
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