Question

A man pushes a cart with force of 120-N at an angle of 50 degrees with the ground. If he walks a horizontal displacement of 20-m going to cashier who’s much work is done!

Answer 1

Answer:

1543 J

Explanation:

The work done by a force when moving an object is given by the equation:

$W=Fd cos \theta$

where:

F is the magnitude of the force applied on the object

d is the displacement of the object

$\theta$ is the angle between the direction of the force and of the displacement

For the  cart pushed in this problem, we have:

$F=120 N$ is the force applied by the man

$d=20 m$ is the displacement of the cart

$\theta=50^{\circ}$ is the angle between the directions of the force and of the displacement

Solving for W, we find the work:

$W=(120)(20)(cos 50^{\circ})=1543 J$