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guajiro [1.7K]
3 years ago
12

Suppose you have two magnets. Magnet A doesn't have its poles labeled, but Magnet B does have a clearly labeled north and south

pole. If these two are brought into contact with one another, which of the following could you expect? 
A. The side of Magnet A that's repelled by Magnet B's south pole must be Magnet A's north pole.

B. The side of Magnet A that's repelled by Magnet B's north pole must be Magnet A's south pole.

C. The side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole.

D. The side of Magnet A that's attracted to Magnet B's north pole must be Magnet A's north pole.
Physics
2 answers:
Serggg [28]3 years ago
7 0
The opposite pole attracts each other and the similar pole repel each other. Which means only C is true.
Elina [12.6K]3 years ago
3 0

Before going to answer this question first we have to know the fundamental principle of magnetism.

A magnet have two poles .The important characteristic of a magnet is that like poles will repel each other while unlike poles will attract each other.

Through this concept the question can be answered  as explained below-

A-As per first option the side of  magnet A is repelled by the south pole  of magnet B. Hence the pole of a must be south .It can't be north as it will lead to attraction.

B-The side of magnet A is repelled by the  north pole of magnet B. Hence the side of A must be  north pole.It can't be a south pole.

C-The side of magnet A is attracted by the south pole  of magnet  B .Hence the side of magnet A must be north.Hence this is right

D-The side of magnet A is attracted by the north pole of magnet B. Hence the side of A must south.It can't be north as it will lead to repulsion.

Hence the option C is right.

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Answer:

t_total = 6.99 s

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we look for t1, it indicates that the distance x = 22m

          v = x / t

           t = x / v

           t₁ = 22/343

           t₁ = 6.41 10-2 s

time t₂

          t₂ = 4500 103/3 108

          t₂ = 1.5 10-5 s

time t₃

          t₃ = 2/343

          t₃ = 5.83 10⁻³

Total time is

         t_total = t₁ + t₂ + t₃

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a 45 kg ice skater initially skating at a velocity of 3 m/s speeds up to a velocity of 5 m/s. calculate the difference in the ma
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Answer: 90 kgm/s

Explanation:

The momentum (linear momentum) p is given by the following equation:

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Where:

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In this situation the skater has two values of momentum:

Initial momentum: p_{1}=m.V_{1}

Final momentum: p_{2}=m.V_{2}

Where:

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So, if we want to calculate the difference in the magnitude of the skater's momentum, we have to write the following equation(assuming the mass of the skater remains constant):

p=p_{2}-p_{1}=m.V_{2}-m.V_{1}

p=m(V_{2}-V_{1})

p=45 kg(5 m/s - 3 m/s)

Finally:

p=90 kgm/s

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