That thing is used as a lever.
There is too much information given, it's hard to understand exactly which variables are important in this problem.
Answer:
Explanation:
moment of inertia of man
= mr² , m is mass of man and r is radius of table .
= 53 x 2.9²
=445.73
angular momentum of runner = mvr , v is velocity of runner .
53 x 3.6 x 2.9 = 553.32
angular momentum of turntable
= Iω , I is moment of inertia and ω is angular velocity of table .
= 76 x .2 = 15.2
Total angular momentum = 553.32 - 15.2
= 538.12
Let the common velocity when the runner comes to rest with respect to turntable be ω.
total moment of inertia of the system
= 445.73 + 76
= 521.73
Applying law of conservation of angular momentum
total initial angular momentum = final angular momentum
538.12 = 521.73 ω
ω = 1.03 rad /s .
Answer:
v = 47.85 m / s
, θ = 64.7º
Explanation:
This is a missile throwing exercise.
Let's find the speed to reach the maximum height, at this point the vertical speed is zero
= v_{oy}^{2} - 2 g y
0 = v_{oy}^{2} - 2gy
v_{oy} = √2gy
let's calculate
v_{oy} = √ (2 9.8 21.3)
v_{oy} = 20.43 m / s
now we can calculate the time it takes to get to this point
vy = v_{oy} - g t
t = v_{oy} / g
t = 20.43 / 9.8
t = 2.08 s
in projectile launching, the time it takes for the body to rise is the same as the time it takes to go down, so the total launch time is
= 2 t
t_{v} = 2 2.08 = 4.16 s
let's use the horizontal throw ratio
x = v₀ₓ t_{v}
v₀ₓ = x / t_{v}
v₀ₓ = 180 / 4.16
v₀ₓ = 43.27 m / s
initial velocity is
v = √ (v₀ₓ² + v_{oy}^{2})
v = √ (20.43² + 43.27²)
v = 47.85 m / s
with an angle of
tan θ = I go / vox
θ = tan⁻¹ (43.27 / 20.43)
θ = 64.7º