Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
wait, I will look my lecture last year
Answer:
129.6% profit
Step-by-step explanation:
1)Firstly in order to find the overall profit you take away $2.70 from $6.20 = $3.50
2)The next step is to put the profit over the amount paid = 3.50/2.70 = 35/27.
3)In order to find the percentaage you multiply 35/27 by 100 = 129.629 recurring. This rounded to 1 decimal place is 129.6%
Thank you for reading, please let me know if I've missed anything out!
I'm going to assume you just mean how do you write the ratio, in which case the answers vary
18:6
18 to 6
or
18/6
Y-5= 3(x-0)
Y-5= 3x
Y= 3x + 5
Hope this helps!