Explanation:
It is known that the molecular weight of
is 111 g/mol. This means that 1 mole of
contains 111 g
.
1 g
= 
As we know that the density of water is 1 g/cc (as 1 ml = 1 cc).
So, 100 ml water = 100 g water. Therefore, in 100 g of water
present will be calculated as follows.
mol
So, in 1000 g water the amount of
present will be calculated as follows.

= 0.09 mol
Hence, the molality of
is 0.09 mol.
According to Raoult's law,

where,
= boiling point constant
For pure 1 kg water,
= 0.52 K.kg/mol
m = molality of solution
Therefore, putting the given values into the above formula as follows.

= 
= 0.0468 K
Therefore, the boiling point will raise by 0.0468 K.
Answer:
The amount of salt in the tank at the end of an additional 10 minutes are 4.38lb.
Explanation:
<u>Situation 1:</u>
Tank with 100 gallons of fresh water
<u>Situation 2:</u>
Tank with 100 gallons of fresh water + water with 0.5lb of salt per gallon
After 10 minutes, as the rate in which the new water is poured is 2 gallons per minute, the result is 20 gallons added (2×10=20) . And taking in account that the water contains 0.5 lb of salt per gallon the amount of salt added is 20×0.5= 10lb of salt.
That amount of salt is now in all the water inside the tank which is 100 gallons+ 20 gallons= 120 gallons. <em>That means that in situation 2 we have 10lb of salt in 120 gallons of water.</em>
That mixture is allowed to leave the tank at a rate of 2 gallons per minute so we will have after 10 minutes: 120 gallons- (2×10) gallons= 100 gallons remaining in the tank. And the amount of salt if we remember that we had 10lb in 120 gallons, now in 100 gallons we will have: (100 gallons × 10lb of salt)/ 120 gallons= 8.33 lb of salt.
<u>Situation 3:</u>
Tank with 100 gallons of water with 8.33lb of salt.
After 10 minutes in which fresh water is poured in the tank at a rate of 9 gallons per minute, the result is: 9×10= 90 gallons added to the tank. So now we have 100+90=190 gallons of water in the tank. <em>That means in situation 3 we have 8.33 lb of salt in 190 gallons of water. </em>
That mixture is leaving the tank at a rate of 9 gallons per minute so we have after 10 minutes: (190- (9×10))= 100 gallons of mixture remaining in the tank.
And the amount of salt if we remember that we had 8.33lb in 190 gallons, now in 100 gallons we will have: (100 gallons × 8.33lb of salt)/ 190 gallons= 4.38 lb of salt.
The Earth's gravitational force accelerates objects when they fall. It constantly pulls, and the objects constantly speed up.