Remark
Supplementary angles add up to 180o.
Givens
<1 = 124
<2 = 2x + 4
I imagine you are looking for either x or <2.
Equation
<1 + <2 = 180 Substitute the givens
124 + 2x + 4 = 180 Collect like terms on the left.
128 + 2x = 180 Subtract 128 from both sides
2x = 180 - 128 Collect like terms on the right
2x = 52 divide by 2
x = 52/2
x = 26 <<<<<<<<< answer
<1 = 124
<2 = 2x + 4 = 2*26 + 4
<2 = 52 + 4
<2 = 56 <<<<<<<< answer
We need choices if you want an exact answer.
Answer:
(-7, -12)
Step-by-step explanation:
4x-3y=8
5x-2y=-11
Is there any of the like terms can be added and the result will be 0? No, so we have to multiple one OR both of the equations to make that one number do that.
(I will try to remove the y like terms so i will multiple both of them by the opposite so both of the ys will be 6)
2(4x-3y=8)
-3(5x-2y=-11)
8x-6y=16
-15x+6y=33
(now the easy part… cancel the 6s and add the equations)
8x+(-15x)=-7x
16+33=49
-7x=49
(divide 49 by -7)
x=-7
Replace x in any of the equations and you’ll get the y value.
4x-3y=8
4(-7)-3y=8
-28-3y=8
-3y=36
y=12
Threfore, there is one solution which is….. (-7,-12)
Answer:
- North Middle School = 10 students
- Central Middle School = 6 students
- South Middle School = 4 students
Step-by-step explanation:
First calculate the total number of students in all the schools:
= 618 + 378 + 204
= 1,200 students
Use this number to calculate the proportion of the total population that a school so that this can then be used to determine the proportion of the 20 delegates they should sent.
North Middle school:
= 618/1,200 * 20
= 10 students
Central Middle School:
= 378 / 1,200 * 20
= 6 students
South Middle School:
= 204/1,200 * 20
= 4 students
Answer: option a
Step-by-step explanation:
You must apply the formula for calculate the distance between the two points. which is shown below:
Therefore, keeping on mind that the points given in the problem are (6, 11), (0, 3), when you substitute values into the formula shown above, you obtain that the distance between these two points is the following:
