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PolarNik [594]
3 years ago
7

How many grams of al are in 4.70 moles?

Chemistry
1 answer:
KIM [24]3 years ago
6 0
Using the formula Mass = mol × Mr

If mol of Al  = 4.7 mol
and Mr of Al = 27 g/mol

then  Mass = 4.7 mol  ×  27g/mol
                   =  126.9 g
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According to the molecular orbital (mo) treatment of the no molecule, what are the bond order and the number of unpaired electro
mojhsa [17]
Attached is the MOT of NO molecule.

1. Bond order is calculated is \frac{\text{number of e- in bonding orbital - number of e- in antibonding molecular orbital }}{2}

In present case, number of e- in bonding orbital = 6
number of e- in anti-bonding orbital = 1
∴ Bond-order = \frac{\text{6-1 }}{2} = 2.5

2. From the attached figure, it can be seen that NO has one unpaired electron in π* orbital.
 

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A student is doing an experiment that stoichiometry says should produce 34.6 grams of product. The student actually makes 25.2 g
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When 91.5 g of isopropyl alcohol which has an empirical formula of C3H8O is burned in excess oxygen gas, how many grams of H2O a
Kobotan [32]

Answer:

109.7178g of H2O

Explanation:

First let us generate a balanced equation for the reaction. This is illustrated below:

2C3H8O + 9O2 —> 6CO2 + 8H2O

Next we will calculate the molar mass and masses of C3H8O and H20. This is illustrated below:

Molar Mass of C3H8O = (3x12.011) + (8x1.00794) + 15.9994 = 36.033 + 8.06352 + 15.9994 = 60.09592g/mol.

Mass of C3H8O from the balanced equation = 2 x 60.09592 = 120.19184g

Molar Mass of H2O = (2x1.00794) + 15.9994 = 2.01588 + 15.9994 = 18.01528g/mol

Mass of H2O from the balanced equation = 8 x 18.01528 = 144.12224g

From the equation,

120.19184g of C3H8O produced 144.12224g of H20.

Therefore, 91.5g of C3H8O will produce = (91.5 x 144.12224) /120.19184 = 109.7178g of H2O

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3 years ago
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