Answer:
m/s²
m/s²


Explanation:
Normal or centripetal acceleration measures change in speed direction over time. Its expression is given by:
Formula 1
Where:
: Is the normal or centripetal acceleration of the body ( m/s²)
v: It is the magnitude of the tangential velocity of the body at the given point
.(m/s)
r: It is the radius of curvature. (m)
Newton's second law:
∑F = m*a Formula ( 2)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
Data




r= 120 m
Problem development
We replace data in formula (1) to calculate centripetal acceleration:

m/s²

m/s²
We replace data in formula (2) to calculate centripetal force Fc) :




m1= mass 1 = 1.1 kg
Vi1 = initial velocity 1 = 2.7 m/s
m2= 2.4 kg
V2i = -1.9 m/s
We assume east as positive and west as negative.
Apply the formulas:
Vf1 = ?

Replacing:



Answer: 3.6 m/s west
Answer:
d = 9.69 cm
Explanation:
given,
mass of the block = 1.2 Kg
spring force constant(k) = 730 N/m
spring is compressed = d = ?
rough patch width = 5 cm
μ_k = 0.44
work done by friction = energy lost




d = 0.0969 m
d = 9.69 cm
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Answer:
the answer is A because I did this in 5th grade