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sasho [114]
4 years ago
15

Which of the following items could be dated by the use of radiocarbon dating?

Physics
2 answers:
rodikova [14]4 years ago
8 0
C) 60,000 year old metamorphic rock. Radio carbon dating is finding out the age of something that has organic material in it 
ololo11 [35]4 years ago
7 0
D
Carbon dating relies on the ratio of Carbon-12 and Carbon-14 in an organic substance
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Often called velocity this is the velocity of an object at a particular moment in time
Yuliya22 [10]
Instantaneous speed?
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3 years ago
Drag the item from the item bank to its corresponding match.
tigry1 [53]
1- first law
2- third law
3- first law
4- second law
5- third law
6- second law
3 0
3 years ago
Read 2 more answers
Please help ASAP! Thank you!
Likurg_2 [28]

Answer:

Sound energy wave is transferred through a substance as a series of compressions.

Explanation:

Sound is caused by regular oscillating that produce regions of compression (high pressure) and rarefaction (low pressure) that move through a substance. Sound not only travels through air, it can travel through any substance, solid, liquid or gas. Whales can hear other whales across whole oceans through water, an Earthquake is low frequency sound moving through the solid Earth

A vibrating object compresses the air and sound waves move from the source, much like waves in water if you drop a stone into it. These sound waves can carry great distances depending on their loudness and frequency.

4 0
3 years ago
Add a vector whose magnitude is 13 with angle 27 degrees to one whose magnitude is 11 with angle 45 degrees? Put the length firs
mafiozo [28]

Answer:

Magnitude of the vector is 23.75\ \text{units} and the direction is 35.23^{\circ}

Explanation:

Magnitude of first vector = |A| = 13\ \text{units}

Angle = \theta_1=27^{\circ}

Magnitude of second vector = |B| = 11\ \text{units}

Angle = \theta_2=45^{\circ}

x component of first vector

A_{x}=|A|\cos\theta_1\\\Rightarrow A_x=13\cos27^{\circ}\\\Rightarrow A_x=11.6\ \text{units}

y component of first vector

A_{y}=|A|\sin\theta_1\\\Rightarrow A_y=13\sin27^{\circ}\\\Rightarrow A_y=5.9\ \text{units}

x component of second vector

B_{x}=|B|\cos\theta_2\\\Rightarrow B_x=11\cos45^{\circ}\\\Rightarrow B_x=7.8\ \text{units}

y component of first vector

B_{y}=|B|\sin\theta_2\\\Rightarrow B_y=11\sin45^{\circ}\\\Rightarrow A_y=7.8\ \text{units}

Adding the magnitudes

C_x=A_x+B_x=11.6+7.8\\\Rightarrow C_x=19.4\ \text{units}

C_y=A_y+B_y=5.9+7.8\\\Rightarrow C_y=13.7\ \text{units}

Magnitude of the sum of the vectors would be

|C|=\sqrt{C_x^2+C_y^2}\\\Rightarrow |C|=\sqrt{19.4^2+13.7^2}=23.75\ \text{units}

The direction would be

\theta=\tan^{-1}\dfrac{C_y}{C_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{13.7}{19.4}\\\Rightarrow \theta=35.23^{\circ}

The magnitude of the vector is 23.75\ \text{units} and the direction is 35.23^{\circ}

4 0
3 years ago
How many arrows of force would be needed in a free body diagram of a rocket taking off from the moon? Ignore any solar system ob
Sophie [7]

#1

When rocket is launched from the moon then there will be two forces on the rocket

1. Due to ejected gases the reaction force on rocket in forward direction

2. due to gravitational attraction of moon

So here we need to draw two arrow on its FBD in which first arrow is in the direction of motion of rocket which will be the reaction force on it while other arrow is opposite to its motion which is due to gravitational attraction force.

So answer would be TWO

#2

When crate is placed on the floor then in order to lift the crate upwards we always need an external force that will counter balance the normal force of crate.

Which mean if we make the normal force to be zero then crate will lift upwards and in order to make it zero we need to apply same force as that of normal force

So here the normal force is given as 150 N so we also need to apply 150 N force in order to lift it upwards


#3

If a person lift a box upwards by some force then we can say by force balance

Force applied by person + Normal force = Weight of the box

F_{app} + F_n = mg

we will plug in all values in it

F_{app} + 150 = 30 * 10

F_{app} = 300 - 150

F_{app} = 150 N

So we applied 150 N force on it

#4

In all cases we need to use force balance

like in case 3

T + T = W

2T = W

T = \frac{W}{2}

so here in 3rd case tension is half of the weight

which will be the least tension in all cases

so answer is CASE 3

7 0
4 years ago
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