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Tju [1.3M]
3 years ago
15

Can someone explain the equation Q = M C delta T or Q = MCΔT Thanks!

Physics
2 answers:
mylen [45]3 years ago
3 0
Q = heat energy , m=mass , c=specific heat , delta T= change in temperature

as you know heat is a form of energy which is <em>usually</em> measured in Joules according to the SI. and also we usually use kilograms for mass.

so you need to know the mass, specific heat, and change in temperature in order to find out the heat energy :)
adell [148]3 years ago
3 0
Q is the quantity of heat energy used to change the temperature of specific mass of certain matter
M is the mass of matter u wanna to change its temperature
C is the specific heat, each substance has its own "C" as specific heat is the quantity of heat to change mass of 1 kg by 1 kalvin deg.
ΔT is the the difference in temp. from and to how much u wanna to change the temp. of your matter 
so if u wanna to change 1L water (for example) which = to 1kg
u wanna to increase its temp. by 2 degrees 
and the "c" is ≈ 4200 then 
the quantity of energy u need to do that is = MCΔT = 1*4200*2 = 8400
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3 years ago
The heater element of a particular 120-V toaster is a 8.9-m length of nichrome wire, whose diameter is 0.86 mm. The resistivity
AleksAgata [21]

Answer:

Power, P = 722.96 watts

Explanation:

It is given that,

Voltage, V = 120 V

Length of nichrome wire, l = 8.9 m

Diameter of wire, d = 0.86 mm

Radius of wire, r = 0.43 mm = 0.00043 m

Resistivity of wire, \rho=1.3\times 10^{-6}\ \Omega-m

We need to find the power drawn by this heater. Power is given by :

P=\dfrac{V^2}{R}

And, R=\rho\dfrac{l}{A}

P=\dfrac{V^2\times A}{\rho\times l}

P=\dfrac{120^2\times \pi (0.00043)^2}{1.3\times 10^{-6}\times 8.9}

P = 722.96 watts

So, the power drawn by this heater element is 722.96 watts. Hence, this is the required solution.    

3 0
3 years ago
Two charges separated by one meter exert a 9 N force on each other. If the charges are pushed to a 3 meter separation, the force
tamaranim1 [39]

Answer:

False

Explanation:

The formula of force that exists between two charges is expressed as;

F = kq1q2/r²

If two charges separated by one meter exert a 9 N force on each other, the;

9 = kq1q2/1²

9 = kq1q2 ..... 1

If the charges are pushed to a 3 meter separation, then;

F =  kq1q2/3²

F =  kq1q2/9 .... 2

Divide both equations;

9/F = (kq1q2)/ kq1q2/9

9/F =  kq1q2 * 9/ kq1q2

9/F = 9

F = 9/9

F = 1N

Hence if the charges are pushed to a 3 meter separation, then the force on EACH charge will be 1N. Hence the answer is False

3 0
3 years ago
If the force applied to an object is not greater than the starting friction, what will happen to the object?
bonufazy [111]

Answer:

Explanation:

the object will not move as the force exerted is not sufficient enough to overcome its force of friction

3 0
3 years ago
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