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AveGali [126]
3 years ago
14

Which measure of an earthquake depends on how close you are to the focus?

Physics
1 answer:
Vsevolod [243]3 years ago
8 0
<span>The intensity of an earthquake is dependent on one's proximity to the focus of the quake, also called the "epicenter" and is based on observations of the shaking of the ground on humans, structures, and the natural landscape.</span>
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miv72 [106K]

Answer: The verb phrase can be found in the last sentence(?

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In a ……………………………….. wave, the particles of the medium vibrate in a direction parallel
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Answer:

4 longitudinal waves

Explanation:

have a beautiful day ahead

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When forming a bond, an atom that has 3 electrons in its second shell and a filled first shell will?
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Macromolecule polymers are assembled by the connecting of monomers. An -OH group is detached from one monomer and a hydrogen atom is detached from an additional in a procedure named dehydration synthesis in the monomers bond. For every subunit supplementary to a macromolecule in which one water molecule is detached. Macromolecule polymers are broken down by breaking bonds among subunits. This procedure is named hydrolysis and is the opposite of dehydration. During hydrolysis the hydrogen atom is supplementary to one monomer and a hydroxyl cluster to the other and by breaking the covalent bond in the middle of the monomers.
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3 years ago
In the far future, astronauts travel to the planet Saturn and land on Mimas, one of its 62 moons. Mimas is small compared with t
Mamont248 [21]

Answer:

a)h_{max}=14536.16 m

b)h = 15687.9 m

c)PD=7.62\% The estimate is low.

Explanation:

a) Using the energy conservation we have:

E_{initial}=E_{final}

we have kinetic energy intially and gravitational potential energy at the maximum height.

\frac{1}{2}mv^{2}=mgh_{max}

h_{max}=\frac{v^{2}}{2g}

h_{max}=\frac{43^{2}}{2*0.0636}

h_{max}=14536.16 m  

b)  We can use the equation of the gravitational force

F=G\frac{mM}{R^{2}}   (1)

We have that:

F = ma    (2)

at the surface G will be:

G=\frac{gR^{2}}{M}

Now the equation of an object at a distance x from the surface.

is:

F=\frac{mgR^{2}}{(R+x)^{2}}

m\frac{dv}{dt}=\frac{mgR^{2}}{(R+x)^{2}}

Using that dv/dt is vdx/dt and integrating in both sides we have:

v_{0}=\sqrt{\frac{2gRh}{R+h}}

h=\frac{v_{0}^{2}R}{2gR-v_{0}^{2}}

h=15687.9

c) The difference is:

So the percent difference will be:

PD=|\frac{14536.16-15687.9}{(14536.16+15687.9)/2}*100%

PD=7.62\%

The estimate is low.

I hope it helps you!

7 0
3 years ago
Which of the following statements about energy in systems is true?
Elena-2011 [213]
Option number three is correct energy can be transformed and moved and released but it can't be destroyed and doesn't disappear.
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3 years ago
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