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Advocard [28]
3 years ago
15

Help please!

Physics
2 answers:
Ne4ueva [31]3 years ago
8 0

Answer:

Spinning permanent magnets within an array of fixed permanent magnets

Explanation:

olchik [2.2K]3 years ago
5 0

Answer:

Definitely Spinning permanent magnets within an array of fixed permanent magnets

Explanation:

Any relative motion between magnets (be they permanent or electromagnetic) and a coil of wire will induce an electric current in the coil.

What will not induce an electric current is the relative motion between the two coils of wire (because there is no change in magnetic field), or the relative motion between two magnets (there are no coils of wire to induce the current into).

<em>Therefore, spinning permanent magnets within an array of fixed permanent magnets does not induce an electric current.</em>

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Answer:

a fundamental force

Explanation:

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8 0
3 years ago
Read 2 more answers
A car can be braked to a stop from the autobahn-like speed of 206 km/h in 190 m. Assuming the acceleration is constant, find its
Llana [10]

Answer:

  • a = - 8.617 \frac{m}{s^2}
  • a =  - 0.8798 \ g
  • Tb = 6.64 \ s
  • \frac{Tb}{Tr} = 16.6

Explanation:

<h3>a and b</h3>

We can use the following formula, from kinematics:

(v_f)^2-(v_i)^2 = 2  \ a \  d

where v_f is the final speed, v_i is the initial speed, a is the acceleration and d the distance traveled.

Knowing that the final speed is zero, and the initial speed is

v_i = 206 \frac{km}{h} = 206 \frac{km}{h} \frac{1000 \ m}{1 \ km} \frac{1 \ h}{3600 \ s} = 57.22 \frac{m}{s}

we obtain

(0)^2-(57.22 \frac{m}{s})^2 = 2  \ a \  190 \ m

a = \frac{ - \ 3,274.13 \frac{m^2}{s^2} }{ 2 \ 190 \ m}

a = - 8.617 \frac{m}{s^2}

Now, knowing that

g = 9.806 \frac{m}{s^2}

then

a = \frac{- 8.617 \frac{m}{s^2}} { 9.806 \frac{m}{s^2} } \ g

a = -  0.8798 \ g

<h3>c</h3>

We can use the following formula

v(t) = v_0 + a t

so

0 =  57.22 \frac{m}{s} - 8.617 \frac{m}{s^2} \ Tb

Tb = \frac{ 57.22 \frac{m}{s} }{ 8.617 \frac{m}{s^2} }

Tb = 6.64 \ s

<h3>d</h3>

\frac{Tb}{Tr} = \frac{ 6.64 \ s }{ 0.4 s }

\frac{Tb}{Tr} = 16.6

3 0
3 years ago
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<span>And the efficiency = work out / heat in </span>
<span>= 3600/9000 </span>
<span>= 0.4 or 40%

Sorry if this does not help.</span>
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