Question

A gas with a volume of 4.0L at a pressure of 205kPa is allowed to expand to a volume of 12.0L. What is the pressure in the container if the temperature remains constant?

Answer 1

Answer:

68.3 kilo Pascal is the pressure in the container.

Explanation:

To calculate the new pressure , we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=205kPa\\V_1=4.0 L\\P_2=?\\V_2=12.0 L$

Putting values in above equation, we get:

$P_2=\frac{P_1V_1}{V_2}$

$=\frac{205 kPa\times 4.0 L}{12.0 L}=68.3 kPa$

68.3 kilo Pascal is the pressure in the container.