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3 years ago

Convert 52 centigrams to grams. 520 g 0.52 g 5,200 g 5.2 g

Chemistry

1 answer:

PIT_PIT [208]3 years ago

5 0

1 cent ----------> 0.01 g
52 cent ---------> g

g = 52 * 0.01

answer 0.52 g

hope this helps!.

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What is the lowest unoccupied molecular orbital in F2?

Juliette [100K]

Answer:

σ*2pₓ, also called $3\sigma_{u}\text{*}$

Explanation:

I have drawn the MO diagram for fluorine below.

Each F atom contributes seven valence electrons, so we fill the MOs of fluorine with 14 electrons.

We have filled the $\pi \text{*2p}_{y}$ and $\pi \text{*2p}_{z}$ MOs.

They are the highest occupied molecular orbitals (HOMOs).

The next unfilled level (the LUMO) is the σ*2pₓ orbital. If you use the symmetry notation, it is called the $3\sigma_{u}\text{*}$ orbital.

This is the orbital that fluorine uses when it acts as an electron acceptor.

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3 years ago

B. If the initial pressure of gas inside the balloon was 1.65 atm, what is the new pressure?

Orlov [11]

Question 1 :

V1/T1 = V2/T2

3.0L/273K = V2/373K

To get the value of Z, cross multiply

3.0L x 373K = 273K x V2

1119 = 273V2

Divide both sides by 273

1119/273 = 273V2/273

4.10L = V2

The new volume is 4.10 liters

Question 2 :

P1/T1 = P2 /T2

P1 = 880 kPA= 880 *10^3 Pa

T1 = 250 K

T2 = 303 K

P2 =?

Substituting for P2

P2 = P1 T2/ T1

P2 = 880 kPa * 303 / 250

P2 = 266,640 kPa/ 250

P2 = 1066.56 kPa.

The new pressure of the gas is 1066.56 kPa

Question 3 :

Given that:

Volume of gas V = 4.80L

(since 1 liter = 1dm3

4.80L = 4.80dm3)

Temperature T = 62°C

Convert Celsius to Kelvin

(62°C + 273 = 335K)

Pressure P = 2.9 atm

Number of moles of gas N = ?

Apply ideal gas equation

pV = nRT

2.9atm x 4.8dm3 = n x (0.0082 atm dm3 K-1 mol-1 x 335K)

13.92 atm dm3 = nx 2.747 atm dm3 mol-1

n = 13.92/2.747

n = 5.08 moles

There are 5.08 moles of gas contained in the sample

Question 4 :

Volume of gas V = 3.47L

(since 1 liter = 1dm3

3.47L = 3.47dm3)

Temperature T = 85.0°C

Convert Celsius to Kelvin

(85.0°C + 273 = 358K)

Pressure P = ?

Number of moles of gas N = 0.100 mole

Apply ideal gas equation

pV = nRT

p x 3.47dm3 = 0.10 x (0.0082 atm dm3 K-1 mol-1 x 358K)

p x 3.47dm3 = 0.29 atm dm3

p = (0.29 atm dm3 / 3.47 dm3)

p = 0.085 atm

If 1 atm = 760 mm Hg

0.085atm = 0.085 x 760

= 64.6 mm Hg

The pressure of the gas is 64.6 mm hg

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3 years ago

Write the chemical equation for the equilibrium that corresponds to Ka. Write the chemical equation for the equilibrium that cor

viva [34]

Answer:

H+AQ=POP

Explanation:

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4 years ago

What is the full meaning of DR.HERC.

n200080 [17]

Answer:

It is

D- DEFINE the problem

R-RESEARCH on the problem

H- Carry out a HYPOTHESIS

E- carry out an EXPERIMENT.

R-Analyse the RESULT

C-summarise the CONCLUSION.

Explanation:

Hope it helps.

5 0

3 years ago

In lab, you calculate the density of an iron rod to be 7.30 g/cm3. The accepted value

OLga [1]

Answer:

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

actual density = 7.80 g/cm³

error = 7.30 - 7.80 = 0.5

We have

$p(\%) = \frac{0.5}{7.8} \times 100 \\ = 6.410256...$

We have the final answer as

Hope this helps you

6 0

3 years ago