Question

When the gases dihydrogen sulfide and oxygen react, they form the gases sulfur dioxide and water vapor. (How would this be written in an equation?)

Answer 1

When the gases dihydrogen sulfide and oxygen react, they form the gases sulfur dioxide and water vapor. so the balanced equation is
2H2S(g) + 3O2(g) → 2SO2(g) + 2H2O(l)
hope it helps

Answer 2

Answer:

The balanced chemical equation can written be as:

$2H_2S (g)+3O_2(g)\rightarrow 2SO_2(g)+2H_2O (g)$

Explanation:

Dihydrogen sulfide = $H_2S$

Oxygen gas = $O_2$

Sulfur dioxide = $SO_2$

Water vapor =$H_2O$

The balanced chemical equation can written be as:

$2H_2S (g)+3O_2(g)\rightarrow 2SO_2(g)+2H_2O (g)$

According to reaction , 2 moles of hydrogen sulfide reacts with 3 moles of oxygen gas to give to 2 moles of sulfur dioxide and 2 moles of water vapors.