The entropy change<span> of the surroundings is driven by heat flow and the heat flow determines the sign of ΔS</span>surr<span>. It can be calculated by the following expression:
</span>ΔSsurr = -(ΔH) / T
We calculate as follows:
ΔSsurr = -13200 / 1337 = 9.87 J/ K mol
Hope this answers the question. Have a nice day.
Pretty sure the answer is B. Attract each other
Therefore, if the block moves from its position of maximum spring stretch to maximum spring compression in 0.25 s, the time required for a full cycle is twice as much; T = 0.5 s.
Answer:
v = 120 m/s
Explanation:
We are given;
earth's radius; r = 6.37 × 10^(6) m
Angular speed; ω = 2π/(24 × 3600) = 7.27 × 10^(-5) rad/s
Now, we want to find the speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator.
The angle will be;
θ = ¾ × 90
θ = 67.5
¾ is multiplied by 90° because the angular distance from the pole is 90 degrees.
The speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator will be:
v = r(cos θ) × ω
v = 6.37 × 10^(6) × cos 67.5 × 7.27 × 10^(-5)
v = 117.22 m/s
Approximation to 2 sig. figures gives;
v = 120 m/s
Answer:
The answer is below
Explanation:
a) Given that the modulus of elasticity (E) = 317 GPa, to find the modulus of elasticity (in GPa) for the nonporous material (
), we use the formula:
b) If the porosity P = 11.1%, then the modulus of elasticity is:
