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viktelen [127]
3 years ago
11

I HAVE 5 MINUTES!!!!!! A block oscillating on the end of a spring moves from its position of maximum spring stretch to maximum s

pring compression in 0.25 s. Determine the period and frequency of this motion​
Physics
1 answer:
Verdich [7]3 years ago
4 0

Therefore, if the block moves from its position of maximum spring stretch to maximum spring compression in 0.25 s, the time required for a full cycle is twice as much; T = 0.5 s.

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If a 90 kg hockey player slows from 18 m/s to 12 m/s over 0.6 s, what is the force exerted by his skates on the ice? A. -540 N B
Zielflug [23.3K]

Answer:

B. -900 kg-m/s2

Explanation:

First of all, we need to calculate the acceleration of the hockey player, which is given by:

a=\frac{v-u}{t}

where

v = 12 m/s is the final speed

u = 18 m/s is the initial speed

t = 0.6 s is the time

Substituting into the formula, we find

a=\frac{12 m/s-18 m/s}{0.6 s}=-10 m/s^2

And now we can calculate the force exerted by using Newton's second law:

F=ma

where m=90 kg is the mass of the hockey player. Substituting into the formula, we find

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5 0
3 years ago
n optician is performing Young's double-slit experiment for her clients. She directs a beam of monochromatic light to a pair of
steposvetlana [31]

Answer:

Explanation:

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screen distance D = 4.5 m

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= 4 x 553

= 2212 nm .

= 2.212 μm

7 0
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I believe this is an example of transferred heat. Are there any multiple choice given?

6 0
3 years ago
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inysia [295]
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v=v0+at. v = v 0 + at.
d=12(v0+v)t d = 1 2 ( v 0 + v ) t or alternatively vaverage=dt. v average = d t.
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Hope this helps ;)


4 0
3 years ago
When the shadow of the moon appears on earths surface what is occuring?
Ket [755]

The moon surface is visible to an observer on earth due to the gravitational force that attracts the moon to the earth. The more massive the body is, the more the smaller body is attracted to the larger body. We can only see the side of the moon due to the speed at which the moon rotates.

6 0
3 years ago
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