Question

How would you write 0x+19y=38 in slope-intercept form?

Answer 1

Basically, we need to isolate y

Assuming 0 is unnecessary:

x + 19y = 38
19y = -x + 38
$y= \frac{-x+38}{19}$
$y= -\frac{x}{19} + \frac{38}{19}$
$y= -\frac{x}{19} +2$



Assuming that 0 is necessary:

0x+19y = 38

0•x is equivalent to 0 so that cancels out x leaving us with

19y = 38

y = 38/19

y = 2


If the 0 is necessary, your answer is y = 2.
If the 0 is unnecessary, your answer is y = -(x/19)+2