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artcher [175]
3 years ago
10

What is the land between two normal faults that may be uplifted to form?

Physics
1 answer:
sergey [27]3 years ago
6 0
I think the land between two faults that may be uplifted are formed into mountians
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Suppose it takes a constant force a time of 6.0 seconds to slow a 2500 kg truck
erastovalidia [21]

Answer:

3.3\cdot 10^3\:\mathrm{N}

Explanation:

Impulse on an object is given by \mathrm{[impulse]}=F\Delta t.

However, it's also given as change in momentum (impulse-momentum theorem).

Therefore, we can set the change in momentum equal to the former formula for impulse:

\Delta p=F\Delta t.

Momentum is given by p=mv. Because the truck's mass is maintained, only it's velocity is changing. Since the truck is being slowed from 26.0 m/s to 18.0 m/s, it's change in velocity is 8.0 m/s. Therefore, it's change in momentum is:

p=2500\cdot 8.0=20,000\:\mathrm{kg\cdot m/s}.

Now we plug in our values and solve:

\Delta p=F\Delta t,\\F=\frac{\Delta p}{\Delta t},\\F=\frac{20,000}{6}=\fbox{$3.3\cdot 10^3\:\mathrm{N}$}(two significant figures).

6 0
3 years ago
A heat pump absorbs heat from the atmosphere at a rate of 30 kW. If work is being done to run this heat pump at a rate of 7.7 kW
Volgvan

Answer:

Option D 3.9

Explanation:

First, you need to use the correct equation which is the following:

COP = Q/W

Where:

Q = heat absorbed

W = work done by the pump

COP = coefficient of perfomance

We have all the data, so, all you need to do is replace in the above expression and you shoould get the correct result:

COP = 30 / 7.7

COP = 3.896

This result you can round it to 3.9. option D.

8 0
3 years ago
PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP
alisha [4.7K]

Answer:

There are 4 liquids in this experiment and red is the least dense of all of them so it should float on top, which it is doing.

The red that you see at the bottom is neither liquid nor is it a part of the experiment.

It is simply the <u>color of the bottom of the container</u> that the experiment was conducted in.

4 0
3 years ago
Read 2 more answers
Waldo needs to know how much force to apply in order to move a 4000-kg object at 2 m/S2. Which law should he refer to
Evgen [1.6K]

bebe xd mexico gana siempre

6 0
3 years ago
An Argon laser (λ = 5.0×102nm) shines down a silica glass fiber-optic cable with index of refraction 1.46. What is the speed of
Yanka [14]

Answer:

The speed of the laser light in the cable, c_f=2.1\times 10^8\ m/s

Explanation:

It is given that,

Wavelength of Argon laser, \lambda=5\times 10^2\ nm=5\times 10^{-7}\ m

Refractive index, n = 1.46

Let c_f is the speed of the laser light in the cable. The speed of light in a medium is given by :

c_f=\dfrac{c}{n}

c_f=\dfrac{3\times 10^8\ m/s}{1.46}

c_f=2.05\times 10^8\ m/s

or

c_f=2.1\times 10^8\ m/s

So, the speed of the laser light is 2.1\times 10^8\ m/s. Hence, this is the required solution.

4 0
4 years ago
Read 2 more answers
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