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Dafna1 [17]
3 years ago
13

An elevator accelerates upward at 1.2 m/s 2 . the acceleration of gravity is 9.8 m/s 2 . what is the upward force exerted by the

floor of the elevator on a(n) 76 kg passenger? answer in units of n.
Physics
1 answer:
Marysya12 [62]3 years ago
8 0
We can find the force by using the following formula;
N = ma +  mg
Fa = ma = 76 x 1.2 = 91.2
Fg = mg = 76 x 9.8 = 744.8
N = 91.2 + 744.8 = 836
So, the force is 836 N.
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Answer:

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Explanation:

From the question we are told that

    The wavelength of the light is  \lambda  =  476.1 \ nm  =  476.1 *10^{-9} \ m

      The  distance between the slit is  d =  0.29 \  mm  =  0.29 *10^{-3} \ m

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