An elevator accelerates upward at 1.2 m/s 2 . the acceleration of gravity is 9.8 m/s 2 . what is the upward force exerted by the floor of the elevator on a(n) 76 kg passenger? answer in units of n.
1 answer:
We can find the force by using the following formula; N = ma + mg Fa = ma = 76 x 1.2 = 91.2 Fg = mg = 76 x 9.8 = 744.8 N = 91.2 + 744.8 = 836 So, the force is 836 N.
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