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3 years ago

Which statement about magnetic poles is accurate?

Physics

1 answer:

Mademuasel [1]3 years ago

6 0

I see I'm late but I believe it's A. , opposites attract. I'm taking the test right now lol

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When a cold air mass catches up with a warm air mass, the resut is often a(n) front.

Alex777 [14]

Answer:

a cold front i think

Explanation:

4 0

3 years ago

A car has a kinetic energy of 103kJ.

sergij07 [2.7K]

Answer: 1200kg

Explanation:

KE = (1/2)mv^2

103kJ = 103000J

103000J = (1/2) * m * (13.1m/s)^2

Solve for m

5 0

2 years ago

Whenever two Apollo astronauts were on the surface of the Moon, a third astronaut orbited the Moon. Assume the orbit to be circu

inysia [295]

Answer:

$v = 1,582 \ \frac{m}{s}$

Explanation:

We know that for circular motion the centripetal acceleration $a_c$ is:

$a_c = \frac{v^2}{r}$

where v is the speed and r is the radius.

The centripetal acceleration for the astronaut must be the gravitational acceleration due to the gravity, as there are no other force. So

$a_c = 1.27 \frac{m}{s^2}$ .

The radius of the orbit must be the radius of the Moon, plus the 270 km above the surface

$r = 1.7 * 10^6 \ m + 270 \ km$

$r = 1.7 * 10^6 \ m + 270 * 10^3 \ m$

$r = 1.7 * 10^6 \ m + 0.270 * 10^6 \ m$

$r = 1.97 * 10^6 \ m$

We can obtain the speed as:

$v^2 = a_c r$

$v = \sqrt{a_c r}$

$v = \sqrt{1.27 \frac{m}{s^2} * 1.97 * 10^6 \ m}$

$v = \sqrt{ 2.509 \ 10^6 \ \frac{m^2}{s^2}}$

$v = 1.582 \ 10^3 \ \frac{m}{s}$

$v = 1,582 \ \frac{m}{s}$

And this is the orbital speed.

7 0

2 years ago

Help me with this please!

alexgriva [62]

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3 0

3 years ago

What is happening at the atomic level to give rise to the observed energy?

ziro4ka [17]

Here is the answer. What is happening at the atomic level to give rise to the observed energy is that the atomic level is affected by the movement of electrons so as to give rise to the observed energy. Hope this answers your question. Have a great day!

6 0

3 years ago