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4 years ago

I need to know what the answer is for question number 10

Chemistry

2 answers:

Dominik [7]4 years ago

8 0

Molarity= moles of solute / liters of solution

2moles/0.75 L= ???? M

Gemiola [76]4 years ago

8 0

The answer is 2.7 Molarity

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What mass of chromium (cr) is contained in 35.8 g of (nh4)2cr2o7 ?

fiasKO [112]

M{(NH₄)₂Cr₂O₇}=2A(N)+8A(H)+2A(Cr)+7A(O)

M{(NH₄)₂Cr₂O₇}=252.065 g/mol

M(Cr)=51.996 g/mol

m{(NH₄)₂Cr₂O₇}/M{(NH₄)₂Cr₂O₇}=m(Cr)/2M(Cr)

m(Cr)=2M(Cr)m{(NH₄)₂Cr₂O₇}/M{(NH₄)₂Cr₂O₇}

m(Cr)=2*51.996*35.8/252.065=14.770 g

m(Cr)=14.770 g

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4 years ago

What is the name for the compound li2so4

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Answer:

Explanation:

Lithium Sulphate

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3 years ago

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An ion of an element can have the same ________ as another element.

Vera_Pavlovna [14]

Answer:

Number of electrons.

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4 years ago

You were making a cream based sauce for your pasta and decided to add some freshly canned tomatoes to the sauce. It tasted fine,

soldier1979 [14.2K]

Answer & explanation:

Canned fruits and vegetables generally have a high acidity and salinity content, in order to prevent the product from spoiling, in addition to enhancing its flavor.

The cream-based sauce started to curdle due to the acidity present in the canned tomatoes.

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4 years ago

A mixture 21.2 g of P and 79.0 g Cl2 reacts completely to form PCl3 and PCl5 as the only products. find the mass of PCl3

IRISSAK [1]

Considering the definition of reaction stoichiometry and limiting reagent, the mass of PCl₃ that could be formed is 38.26 grams.

In first place, you must know that the balanced reaction is:

4 Cl₂ + 2 P → PCl₃ + PCl₅

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Cl₂: 4 moles
P: 2 moles
PCl₃: 1 mole
PCl₅: 1 mole

The molar mass of the compounds is:

Cl₂: 70.9 g/mole
P: 31 g/mole
PCl₃: 137.35 g/mole
PCl₅: 208.25 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Cl₂: 4 moles× 70.9 g/mole = 283.6 grams
P: 2 moles× 31 g/mole= 62 grams
PCl₃: 1 mole× 137.35 g/mole= 137.35 grams
PCl₅: 1mole× 208.25 g/mole= 208.25 grams

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 62 grams of P reacts with 283.6 grams of Cl₂, 21.2 grams of P reacts with how much mass of Cl₂?

$mass of Cl_{2}=\frac{21.2 grams of Px283.6 grams of Cl_{2} }{62 grams of P}$

mass of Cl₂= 96.97 grams

But 96.97 grams of Cl₂ are not available, 79 grams are available. Since you have less mass than you need to react with 21.2 grams of P, Cl₂ will be the limiting reagent.

Then, it is possible to determine the mass of PCl₃ produced by another rule of three, using the limiting reagent: if by stoichiometry 283.6 grams of Cl₂ produce 137.35 grams of PCl₃, 79 grams of Cl₂ how much mass of PCl₃ will be formed?

$mass of PCl_{3}=\frac{137.35 grams of PCl_{3}x79 grams of Cl_{2} }{283.6grams of Cl_{2}}$

mass of PCl₃= 38.26 grams

In summary, the mass of PCl₃ that could be formed is 38.26 grams.

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