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worty [1.4K]
3 years ago
11

When the mass of the boron atom is calculated, the mass of the electrons is ignored. Why is the mass of the electrons ignored?

Chemistry
2 answers:
nirvana33 [79]3 years ago
8 0
Answer. Because electron mass is so insignificant compared to proton and neutron mass that it CAN be ignored.
Pavel [41]3 years ago
5 0

Answer:

Because electron mass is so insignificant compared to proton and neutron mass that it can be ignored.

Explanation:

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What is the volume of a 5.30g piece of aluminum? The density for aluminum is 2.70mL
Makovka662 [10]

Answer:

1.96mL

Explanation:

Density = mass/volume, and rearranged to solve for volume, volume = mass/density.

So:

volume = 5.30g/2.70g/mL = 1.96mL (assuming your unit was g/mL for density)

7 0
3 years ago
Cuando se quema 1 mol de metano –o sea, 16 g–, se desprenden 802
Anvisha [2.4K]

Answer:

1 gramo de metano aporta 50.125 kilojoules.

1 gramo de metano aporta 48.246 kilojoules.

Explanation:

La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo (Q), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto (\bar {Q}), en kilojoules por mol, dividido por su masa molar (M), en gramos por mol:

Q = \frac{\bar Q}{M} (1)

A continuación, analizamos cada caso:

Metano

Q = \frac{802\,\frac{kJ}{mol} }{16\,\frac{g}{mol} }

Q = 50.125\,\frac{kJ}{g}

1 gramo de metano aporta 50.125 kilojoules.

Octano

Q = \frac{5500\,\frac{kJ}{mol} }{114\,\frac{g}{mol} }

Q = 48.246\,\frac{kJ}{mol}

1 gramo de metano aporta 48.246 kilojoules.

3 0
2 years ago
Helppp Mee?!?! correct answer plzzzz??!!!
maks197457 [2]
The correct answer is:

3) Earthquakes can be caused by volcanic eruptions.

You were right :)
8 0
3 years ago
Read 2 more answers
Q2. Which of the following molecules may show.
jonny [76]

Answer:

I think is answer

CH3cl3

5 0
3 years ago
Why is it useful to use moles to measure chemical quantities?
PtichkaEL [24]
It takes into account the different molecular masses of the different chemicals by providing a fixed and standardised number of molecules/ atoms for chemicals to be measured
6 0
3 years ago
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