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nordsb [41]
4 years ago
6

The extent of a compound's dissolving is based on the thermodynamic quantities of enthalpy and entropy. The enthalpy of dissolvi

ng depends on the -Choose... the number of arrangement strength of attraction /other ions present- between the ions in the solid-state and between the ions and-Choose...the container/ the temperature/the solvent. The entropy of dissolving is usually thermodynamically -Choose... favored/ disfavored because the ions have -Choose...stronger attractions/more available arrangements/greater organization- when dissolved.
Chemistry
1 answer:
castortr0y [4]4 years ago
8 0

Answer:

1)strength of attraction

2)the solvent.

3) favored

4)more available arrangements

Explanation:

When a solute is dissolved in a solvent, the ions that have been trapped in the solid become free and the free ions increases the number of particles in solution thereby increasing the entropy of the system. Increase in entropy is favourable to dissolution. Entropy is defined as the degree of disorder in a system.

Dissolution also depends on the ability of solute to effectively interact with the solvent,that is, a enthalpy of dissolution.

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Which of the following mass units is the largest? a) 1 cg b) 1 dg c) 1 mg d) 1 ng
N76 [4]

Answer: option b) 1 dg

Explanation:

1) These are the different equivalences of those quantities:

a) 1 g = 100 cg ⇒ 1 cg = 0.01 g

b) 1 g = 10 dg ⇒ 1 dg = 0.1 g

c) 1 g = 1000 mg ⇒ 1 mg = 0.001 g

d) 1g = 10⁹ g ⇒ 1 ng = 10 ⁻⁹g

2) Now that you have all the masures in grams you can compare:

0.1g > 0.01g > 0.001g > 10 ⁻⁹g

3) So, the largest value is 0.1g which is 1 dg.

4 0
4 years ago
Read 2 more answers
A compound is found to contain 58.80 % xenon, 7.166 % oxygen, and 34.04 % fluorine by mass. what is the empirical formula for th
marissa [1.9K]
To make it easier, assume that we have a total of 100 g of a compound. Hence, we have 58.80g of xenon, 7.166g of oxygen, and 34.04g of fluorine. 
Know we will convert each of these masses to moles by using the atomic masses:

58.8/131.3 = 0.45 mole of Xe
7.166/16 = 0.45 mole of O
34.04/19 = 1.79 mole of F

Now, we will divide all the mole numbers by the smallest among them and get the number of atoms in the compound:

Xe = 0.45/0.45 = 1
O = 045/0.45 = 1
F = 1.79/0.45 = 3.98 = 4

So, the empirical formula of the compound XeOF₄
6 0
3 years ago
Which property of water causes water drops to bead on a freshly waxed car?
astraxan [27]

Answer:

Cohesive forces are greater than adhesive forces  

Step-by-step explanation:

The attractive forces between water molecules and the wax on a freshly-waxed car (adhesive forces) are quite weak.

However, there are strong attractive forces (cohesive forces) between water molecules.

The water molecules are only weakly attracted to the wax, so the cohesive forces pull the water molecules together to form beads .

3 0
3 years ago
) A children’s liquid cold medicine has a density of 1.23 g/mL. If a child is to take 2.5 tsp in a dose, what is the mass in gra
vekshin1

The relation between density and mass and volume is

Density=\frac{Mass}{volume}

the dose required is 2.5 tsp

each tsp contain 5mL

So dose required in mL = 2.5 X 5 = 12.5 mL

the mass will be calculated using following formula

Mass=DensityXvolume

Mass=1.23\frac{g}{mL}X12.5mL= 15.38g

The mass of dose in grams will be 15.38 g


5 0
4 years ago
As a scuba diver descends under water, the pressure increases. At a total air pressure of 2.73 atm and a temperature of 25.0 ∘C,
Svetradugi [14.3K]

Answer:

1.33 x 10⁻³ mol/L

Explanation:

The solubility of a gas in a liquid is directly proportional to its partial pressure .This is know as Henry´s law and is given by the formula:

S(g) = Kh  x P

where  S = solubility of the gas

           Kh = henry´s constant for the gas

           P = partial pressure of the gas above solution

we are told to assume that the composition of the air in the tank is the same as on land, hence its partial pressure and we know nitrogen composition in air is 78 %, so the partial pressure of N₂ is:

P N₂ = 0.78 x 2.73 atm =  2.13 atm

Now we can calcualte the solubility as follows:

S N₂ = 6.26 x 10⁻⁴ mol / L·atm  x 2.13 atm = 1.33 x 10⁻³ mol/ L          

7 0
4 years ago
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