Answer:
384.2 K
Explanation:
First we convert 27 °C to K:
- 27 °C + 273.16 = 300.16 K
With the absolute temperature we can use <em>Charles' law </em>to solve this problem. This law states that at constant pressure:
Where in this case:
We input the data:
300.16 K * 1600 m³ = T₂ * 1250 m³
And solve for T₂:
T₂ = 384.2 K
(46.972* 69.472% + 48.961*21.667% + <span>49.954*8.8610%)/100% =
</span>= 46.972* 0.69472 + 48.961*0.21667 + 49.954*0.088610 =47.667 u
0.23cL because 0.023mL= 23.0L so 23.0L= 0.23cL
Answer:
2) Add a solution of NaBr
Explanation:
Lead (II) bromide is an inorganic powdery substance that has a solubility in water of 0.973 g/100 mL at 20°C. It is insoluble in alcohol but is soluble in alkali, ammonia, NaBr, and KBr
PbBr₂ is slightly soluble in ammonia, and it reacts with NaOH to produce Pb(OH)₂ and NaBr
Therefore, the best solution for dissolving PbBr₂(s) is NaBr
Answer:
The answer to your question is the letter A. 1
Explanation:
Data
Chemical reaction
(NH₄)₂CO₃ ⇒ NH₃ + CO₂ + H₂O
Reactants Elements Products
2 Nitrogen 1
1 Carbon 1
8 Hydrogen 5
3 Oxygen 3
This reaction is unbalanced
(NH₄)₂CO₃ ⇒ 2NH₃ + CO₂ + H₂O
Reactants Elements Products
2 Nitrogen 2
1 Carbon 1
8 Hydrogen 8
3 Oxygen 3
Now, the reaction is balanced,
The coefficient for Carbon dioxide is 1