Answer:
The distance of the traveled is 375 m.
Explanation:
Formula to be use for Motions Along a Straight Line
v=v_{0} +atv=v0+at equation 1
x=v_{0} t + \frac{1}{2} at^2x=v0t+21at2 equation 2
where
vv is the final velocity, unit is in m/s
v_{0}v0 is the initial velocity, unit is in m/s
xx is the distance, unit is in meters (m)
aa is the acceleration, unit is in m/s^2s2
tt is the time duration of motion, unit is in seconds (s)
For the given information
v_{0}=0v0=0 because the car starts from rest
v=50m/sv=50m/s
t=15st=15s
Solving the problem
1. Using equation 1, solve for the acceleration
v=v_{0} +atv=v0+at
50 m/s = 0 + a (15 s)
Divide both sides of the equation by 15 s, we get:
a = \frac{50 m/s}{15s}15s50m/s
a = 3.33 m/s^2s2
2. Using equation 2, substitute the value of the acceleration then solve for x
x=v_{0} t + \frac{1}{2} at^2x=v0t+21at2
x =0+\frac{1}{2} (3.33m/s^2)(15s)^2x=0+21(3.33m/s2)(15s)2
x = 375 m
Therefore, the distance the car has traveled is 375 m within 15 seconds.
To learn more about this topic, just click on the following links:
Definition of acceleration
https://brainly.ph/question/2048479
Additional examples
https://brainly.ph/question/104912
https://brainly.ph/question/503065
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