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OLga [1]
3 years ago
10

How can the speed of solvent molecules be slowed down?

Physics
1 answer:
jarptica [38.1K]3 years ago
4 0

Answer:

Explanation:

lower the temperature  -the  higher the temp the more energy the molecules absorb.  The more energy they have the more they move

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Electric current passing through a human body can be dangerous, even fatal, depending on the amount of current, the duration of
Sati [7]

Answer:

V for dry skin = 41.83 volts

V for wet skin = 0.196 volts

Explanation:

The relationship between current and voltage is given as follows by Ohm's Law:

V = IR

where,

V = voltage

I = Current

R = Resistance

FOR DRY SKIN:

V = Vd = ?

I = 89 μA = 89 x 10⁻⁶ A

R = 4.7 x 10⁵ Ω

Therefore,

Vd = (89 x 10⁻⁶ A)(4.7 x 10⁵ Ω)

<u>Vd = 41.83 volts</u>

FOR WET SKIN:

V = Vw = ?

I = 89 μA = 89 x 10⁻⁶ A

R = 2200 Ω

Therefore,

Vd = (89 x 10⁻⁶ A)(2200 Ω)

<u>Vd = 0.196 volts</u>

7 0
4 years ago
A 0.500-kg mass suspended from a spring oscillates with a period of 1.18 s. How much mass must be added to the object to change
olga55 [171]

Answer:

<em> The add mass = 5.465 kg</em>

Explanation:

Note: Since the spring is the same, the length and Tension are constant.

f ∝ √(1/m)........................ Equation 1  (length and Tension are constant.)

Where f = frequency, m = mass of the spring.

But f = 1/T ..................... Equation 2

Substituting Equation 2 into equation 1.

1/T ∝ √(1/m)

Therefore,

T ∝ √(m)

Therefore,

T₁/√m₁ = k

where k = Constant of proportionality.

T₁/√m₁ = T₂/√m₂ ........................ Equation 3

making m₂ the subject of the equation

m₂ = T₂²(m₁)/T₁²........................... Equation 4

Where T₁ = initial, m₁ = initial mass, T₂ = final period, m₂ = final mass.

<em>Given: T₁ = 1.18 s m₁ = 0.50 kg, T₂ = 2.07 s.</em>

<em>Substituting into equation 4</em>

<em>m₂ = (2.07)²(0.5)/(1.18)²</em>

<em>m₂ = 4.285(1.392)</em>

<em>m₂ = 5.965 kg.</em>

Added mass = m₂ - m₁

Added mass = 5.965 - 0.5

Added mass = 5.465 kg.

<em>Thus the add mass = 5.465 kg</em>

7 0
3 years ago
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