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AlexFokin [52]
3 years ago
14

A force of 334 N has a work on an object of 823 J, what is the displacement that was made

Physics
1 answer:
Greeley [361]3 years ago
8 0

Answer: 2.46m

Explanation:

Given that:

force = 334 N

Work on an object = 823 J

Displacement = ?

Recall that work is done when force is applied on an object over a distance (when the object is displaced in a particular direction)

i.e Work = Force x Displacement

823J = 334 N x displacement

Displacement = 823J / 334N

Displacement = 2.46m

Thus, a displacement of 2.46 metres was made in the work.

in that work

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Explanation:

<u>Coulomb's Law:</u> The electrostatic force between two charge particles Q: and Q2 is directly proportional to product of magnitude of charges and inversely proportional to square of separation distance between them.

Or,   \vec{F}=k \frac{Q_{1} Q_{2}}{r^{2}}

Where Q1 and Q2 are magnitude of two charges and r is distance between them:

<u>Given:</u>

Q1 = Charge near top of cloud = 48.8 C

Q2 = Charge near the bottom of cloud = -41.7 C

Force between charge at top and bottom of cloud (i.e. between Q: and Q2) (F) = 7.98 x 10^6N

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<u>So,</u>

\begin{aligned}&7.98 \times 10^{6}=\left(8.99 \times 10^{9} \mathrm{Nm}^{2} / \mathrm{C}^{2}\right) \frac{48.8 \mathrm{C} \times 41.7 \mathrm{C}}{\mathrm{r}^{2}} \\&r=\sqrt{\frac{1.8294 \times 10^{13}}{7.98 \times 10^{6}}}=1.514  \times 10^{3} \mathrm{~m}=1.51 \mathrm{~km}\end{aligned}

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The electric current in a wire is 1.5A. How many electrons flow past a given point in a time of 2s?
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Answer:

The amount of electrons that flow in the given time is 3.0 C.

Explanation:

An electric current is defined as the ratio of the quantity of charge flowing through a conductor to the time taken.

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It is measure in Amperes and can be measured in the laboratory by the use of an ammeter.

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