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3 years ago

Which of these observations helped Rutherford determine that atoms have tiny, dense, positively charged nuclei?

Chemistry

1 answer:

gladu [14]3 years ago

5 0

The third reason helped Rutherford to discover the nucleus.

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Did Adam Jackson win by

devlian [24]

Answer:

by a number

Explanation:

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3 years ago

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What type of circuit is illustrated?

Ber [7]

I believe it's B: series circuit

good luck

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3 years ago

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Carbon dioxide (CO2) is the gas that is mainly responsible for global warming (the greenhouse effect). The burning of fossil fue

Nesterboy [21]

Answer:

$1.7\cdot 10^{15} g$

Explanation:

Glucose reacts with oxygen do produce carbon dioxide and water:

$C_6H_12O_6 (s) + 6 O_2 (g)\rightarrow 6 CO_2 (g) + 6 H_2O (l)$

Given a daily mass of glucose:

$m_1 = 5.0\cdot 10^2 g$

Find moles of glucose:

$n_1 = {5.0\cdot 10^2 g}{180.156 g/mol} = 2.775 mol$

From stoichiometry of this equation, moles of carbon dioxide can be found by multiplying this amount by 6:

$n_2 = 2.775 mol\cdot 6=16.65 mol$

Convert this into mass using the molar mass of carbon dioxide:

$m_2 = 16.65 mol\cdot 44.01 g/mol = 732.8 g$

This is the mass of carbon dioxide per person per day. Multiply by the population and by the number of days to get the total mass:

$732.8 \frac{g}{person\cdot day}\cdot 365 days\cdot 6.5\cdot 10^9 people = 1.7\cdot 10^{15} g$

5 0

3 years ago

The temperature in a town started out at 55 degrees. By the end of the day the temperature dropped to -6 degrees.

garik1379 [7]

Answer:

The choice of the answer is fourth option that is -61 degrees.

Therefore the temperature drop is -61°Centigrade.

Explanation:

Given:

The temperature in a town started out at 55 degrees

Start temperature = 55°Centigrade. (Initial temperature)

End of the Day = -6°Centigrade. (Final temperature)

To Find:

How far did the temperature drop?

Solution:

We will have,

$\textrm{Temperature drop}=\textrm{Final temperature}-\textrm{Initial temperature}$

Substituting the above values in it we get

$\textrm{Temperature drop}=-6-55\\\\\therefore \textrm{Temperature drop}=-61\° centigrade$

Therefore the temperature drop is -61°Centigrade.

4 0

3 years ago

A 0.89% (w/v) sodium chloride solution is referred to as physiological saline solution because it has the same concentration of

maks197457 [2]

1) 0.89% m/v = 0.89 grams of NaCl / 100 ml of solution

=> 8.9 grams of NaCl in 1000 ml of solution = 8.9 grams of NaCl in 1 liter of solution

2) Molarity = M = number of moles of solute / liters of solution

=> calculate the number of moles of 8.9 grams of NaCl

3) molar mass of NaCl = 23.0 g /mol + 35.5 g/mol = 58.5 g / mol

4) number of moles of NaCl = mass / molar mass = 8.9 g / 58.5 g / mol = 0.152 mol

5) M = 0.152 mol NaCl / 1 liter solution = 0.152 M

Answer: 0.152 M

4 0

3 years ago