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3 years ago

Which of these observations helped Rutherford determine that atoms have tiny, dense, positively charged nuclei?

Chemistry

1 answer:

gladu [14]3 years ago

5 0

The third reason helped Rutherford to discover the nucleus.

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Stels [109]

Answer:

Explanation:

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2 years ago

Here is my question only answer if you understand this question

sasho [114]

1- false
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8 0

3 years ago

Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B How many boxes of B would be required to make 30

Iteru [2.4K]

Mass box C is 10+5. (So C is 15)

But if C was 30, how many times could you put B (5) into it?

30/5 = 6

You would need 6 boxes of B to make 30 grams of C.

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3 years ago

Read 2 more answers

Antibiotics are a type of medicine that kills bacteria. Antibiotics can be used to fight bacterial infections. Which of the foll

AysviL [449]

Answer:

Antibiotics are strong medicines that treat bacterial infections. Antibiotics won't treat viral infections because they can't kill viruses. You'll get better when the viral infection has run its course. Common illnesses caused by bacteria are urinary tract infections, strep throat, and some pneumonia.

Explanation:

antibiotics can treat bacterial infections, such as:

Most sinus infections.

Strep throat.

Urinary tract infections.

Pneumonia.

Most ear infections (otitis media)

Nasty bacterial skin infections (impetigo)

plz mark brainliest

7 0

3 years ago

A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container. Since Kr is expensive, you wish to re

Elena-2011 [213]

Answer:

a) 24.31 g

b) 16.69 g

Explanation:

A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container.

After the CO2 is completely removed by absorption with NaOH(s), the pressure in the container is 0.193 atm.

Therefore, Pressure of Kr = 0.193 atm

Pressure of CO2 = 0.729 - 0.193 = 0.536 atm

Their mole fraction can be also determined as follows:

CO2 = $\frac{Presssure due to CO_2}{Total pressure}$

CO2 = $\frac{0.536}{0.729}$

= 0.735

Also; for Kr ; we have

Kr = $\frac{0.193}{0.729}$

Kr = 0.265

Molar mass of CO2 = 44 g/mol

Molar mass of Kr = 83.78 g/mol

Mass of CO2 = mole fraction * molar mass = 0.735 * 44 = 32.34

Mass of Kr = 0.265 * 83.78 = 22.20

Total mass = 32.34 +22.20 = 54.54

The Percentage of gas in mixture is as follows:

% CO2 = $\frac{32.34}{54.54}$ * 100 %

= 0.5930

= 59.30%

(a) Mass of CO2 in mixture = 0.5930* 41 g = 24.31 g

% Kr = $\frac{22.20}{ 54.54}$ * 100 %

= 0.407

= 40.70 %

(b) Mass of Kr in mixture = 0.407 * 41 = 16.69 g

4 0

3 years ago