Answer:
See explaination
Explanation:
The mole balance for a constant-volume batch reactor is given such as, For a first-order isothermal reaction, the time to reach a given conversion is the same for constant-pressure and constant-volume reactors. Also, the time is the same for a reaction of any order if there is no change in the number of moles.
Please kindly check attachment for the step by step solution of the given problem.
The theoretical yield of NaBr given that 2.36 moles of FeBr₃ reacts is 7.08 moles
<h3>Balanced equation </h3>
2FeBr₃ + 3Na₂S → Fе₂S₃ + 6NaBr
From the balanced equation above,
2 moles FeBr₃ reacted to produce 6 moles of NaBr
<h3>How to determine the theoretical yield of NaBr</h3>
From the balanced equation above,
2 moles FeBr₃ reacted to produce 6 moles of NaBr
Therefore,
2.36 moles FeBr₃ will react to produce = (2.36 × 6) / 2 = 7.08 moles of NaBr
Therefore,
Thus, the theoretical yield of NaBr is 7.08 moles
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Answer:
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Answer:
0.30M HOAc
Explanation:
Given 250.0ml (0.96M HOAc) => 800ml(??M HOAc)
Use the dilution equation...
(Molarity x Volume)concentrated soln = (Molarity x Volume)dilute soln
(0.96M)(250.0ml) = (Molarity diluted soln)(800ml)
Molarity diluted soln = (0.96M)(250.0ml)/(800ml) = 0.30M HOAc
