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4 years ago

The sun is the ___________ of all the energy that moves though food

Physics

2 answers:

KATRIN_1 [288]4 years ago

4 0

Source; producers get energy from the sun, consumers eat producers, and so on and so forth

Marta_Voda [28]4 years ago

3 0

The sun is the source of all the energy that moves through food. It helps the plants to grow which in turn become food that we and other animals eat.

Hope it helps :)

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Mega rayquaza and zygarde 100% form vs lunala, solgaleo, and red's mega charizard

Nezavi [6.7K]

Answer:

That right there is what caused the world to end my friend

Explanation:

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3 years ago

Five friends each do the same amount of work lifting crates up onto shelves. The time it took each person are shown below in the

hichkok12 [17]

Amy 1.5 Andrew 1.7 Tom 2.2 Meg 2.5 Ryan 3.2

8 0

3 years ago

A 1000 kg satellite and a 2000 kg satellite follow exactly the same orbit around the earth. What is the ratio F1/F2 of the gravi

Tamiku [17]

Answer:

the ratio F1/F2 = 1/2

the ratio a1/a2 = 1

Explanation:

The force that both satellites experience is:

F1 = G M_e m1 / r² and

F2 = G M_e m2 / r²

where

m1 is the mass of satellite 1
m2 is the mass of satellite 2
r is the orbital radius
M_e is the mass of Earth

Therefore,

F1/F2 = [G M_e m1 / r²] / [G M_e m2 / r²]

F1/F2 = [G M_e m1 / r²] × [r² / G M_e m2]

F1/F2 = m1/m2

F1/F2 = 1000/2000

F1/F2 = 1/2

The other force that the two satellites experience is the centripetal force. Therefore,

F1c = m1 v² / r and

F2c = m2 v² / r

where

m1 is the mass of satellite 1
m2 is the mass of satellite 2
v is the orbital velocity
r is the orbital velocity

Thus,

a1 = v² / r ⇒ v² = r a1 and

a2 = v² / r ⇒ v² = r a2

Therefore,

F1c = m1 a1 r / r = m1 a1

F2c = m2 a2 r / r = m2 a2

In order for the satellites to stay in orbit, the gravitational force must equal the centripetal force. Thus,

F1 = F1c

G M_e m1 / r² = m1 a1

a1 = G M_e / r²

also

a2 = G M_e / r²

Thus,

a1/a2 = [G M_e / r²] / [G M_e / r²]

a1/a2 = 1

4 0

3 years ago

Hot air balloon with a kinetic energy of 76550J and a mass of 1890kg. what’s the velocity?

lukranit [14]

Answer:

$K.E = \frac{1}{2} m {v}^{2} \\ 76550 = \frac{1}{2} (1890) {v}^{2} \\ {v}^{2} = \frac{76550}{945} \\ = 81.005 \\ v = \sqrt{81.005} \\ v \approx \: 9m. {sec}^{ - 1}$

6 0

3 years ago

Two identical spheres with m=3 kg each are rigidly attached to the rotating light rigid structure. The velocity of the spheres i

Dennis_Churaev [7]

Answer:

Angular momentum of the system is 4.8 kg m^2/s

Explanation:

As we know that the angular momentum of the system of masses is given as

$L = 2I\omega$

here we have

$I = m(0.2 + 0.4)^2$

$I = 3(0.6)^2$

now we also know that

$\omega = \frac{v}{0.2 + 0.4}$

$0.6 \omega = 2 m/s$

now we have

$L = 2(2)(0.6)(2)$

$L = 4.8 kg m^2/s$

3 0

3 years ago