The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.
<h3>Hooke's Law</h3>
Hooke's law states that the force applied to an elastic material is directly proportional to its extension, provided its elastic limit is not exceeded.
To calculate the amount of work done by Hooke's law, first, we need to find the force constant of the spring.
Formula:
- F = ke................. Equation 1
Where:
- F = Force applied
- k = Spring constant
- e = extension
make k the subject of the equation
- k = F/e................ Equation 2
From the question,
Given:
- F = 450 N
- e = 30 cm = 0.3 m
Substitute these values into equation 2
Finally, To find the work done in stretching the spring from 50 cm to 80 cm, we use the formula below.
- W = ke²/2........... Equation 3
Where:
- W = Work done
- k = spring constant
- e = extension
Also, From the question,
Given:
- e = (80-50) = 30 cm = 0.3 m
- k = 1500 N/m
Substitute these values into equation 3
- W = 1500(0.3²)/2
- W = 67.5 J.
Hence, The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.
Learn more about Hooke's law here: brainly.com/question/12253978
Answer:
<em>Both kinetic energies are equal</em>
Explanation:
<u>Kinetic Energy
</u>
Is the type of energy of an object due to its state of motion. It's proportional to the mass and the square of the speed.
The equation for the kinetic energy is:
Where:
m = mass of the object
v = speed of the object
The kinetic energy is expressed in Joules (J)
There are two cars:
Car (A) with mass ma=500 kg and speed va= 2 m/s
Car (B) with mass mb=20,000 gr and speed vb= 10 m/s
Calculate the kinetic energy of both cars:
To calculate the Kb, the mass must be expressed in kg:
mb=20,000/1,000 =20 Kg
Both kinetic energies are equal
<span>The primary service used by stations to exchange mac frames when the frame must traverse the ds to get from a station in one bss to a station in another bss is Distribution
In this type of service, the bss is required in order to build the basic building block for the wireless LAN</span>
The fact that the woman falls at a constant velocity means its acceleration is zero.
For Newton's second law, the resultant of the forces acting on a body is equal to the product between the mass m of the body and its acceleration a:
In our problem, the acceleration is zero, so the resultant of the forces should be zero as well.
Only two forces are acting on the woman: the air resistance R (upward, 500 N) and the weight W (downward). The resultant of these two forces is zero, so
and since the air resistance R is 500 N, then the weight (the gravitational force) of the woman is 500 N as well.