Answer:
The magnitude of force per unit length of one wire on the other is 
and the direction is away from one another
The magnitude of force per unit length of one wire on the other is and the direction is towards each other.
Explanation:
= Vacuum permeability = 
= Current in first wire = 2.9 A
= Current in second wire = 5.3 A
r = Gap between the wires = 11 cm
Force per unit length
The magnitude of force per unit length of one wire on the other is and the direction is away from one another
The magnitude of force per unit length of one wire on the other is and the direction is towards each other.
Answer:
The force each one experienced
Explanation:
Hope this helps :)
Speed=distance/time
distance = 10,000 m
time= 27 min 30.42s but we need to convert that completely to seconds
(27x60)+30.42= 1650.12 rounded to 1650
speed=10,000/1650.12
speed=6.059063
Because when we do sig dig we round to the least number of digits we would round to 4 because 1650.12 gets rounded to 1650
so 6.059 m/s
Using momentum balance, we can say that the momentum
before the strike and after the strike are equal. Therefore:
m1 v1 + m2 v2 = m’ v’
However the door is not moving before the strike therefore
v2 = 0:
0.010 kg * 450 m/s + 0 = (7.010 kg) v’
<span>v’ = 0.64 m/s </span>
The first problem cannot be solve because you did give the distance or length of the rope, because work = distance x force. i can only solve the the second problem. since the bucket is moving up then force due to gravity is going down, then the net force is:
Fnet = F1 - Fg
where Fg = mg
g is the accelaration due to gravity ( 9.81 m/s^2)
Fnet = 57.5 N - (3.9 kg)(9.81) N
Fnet = 19.24 N
