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Valentin [98]
3 years ago
9

What is a moment of a force

Physics
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

In physics and mechanics, torque is the rotational equivalent of linear force. It is also referred to as the moment, moment of force, rotational force or turning effect, depending on the field of study. The concept originated with the studies by Archimedes of the usage of levers

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3. What is Newton's 1st Law?
pishuonlain [190]

Answer:

A

Explanation:

for every action there is an equal and opposite reaction

3 0
3 years ago
Samuel adds a teaspoon of salt to a glass of water. He notices that the salt disappears. Samuel takes a sip to discover that the
nirvana33 [79]
<span>The answer is physical change. This is a kind of change moving the form of a chemical substance, but not its chemical arrangement. Physical changes are used to isolate combinations into their constituent compounds, but cannot typically be used to distinct compounds into chemical elements or simpler compounds. When the salt dissolve in water it is a physical change. The chemical arrangement of the salt is not altered.</span>
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4 years ago
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A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance x from the 50
Rom4ik [11]

Answer:

x=0.01457 m

Explanation:

From parallel axis theorem

I=Icm+mh²

where h=x

The rotational inertia about its center of mass is

Icm=mL²/12

where L=1.0 m

Thus T=4.8s  we obtain

T=2\pi \sqrt{\frac{mL^{2}/12+mx^{2}  }{mgx} }\\ T=2\pi \sqrt{\frac{L^{2} }{12gx}+x/g }\\ T^{2}=4\pi^{2}(\frac{L^{2} }{12gx}+x/g )/x\\ T^{2}x=\frac{\pi^{2} L^{2} }{3g}+(\frac{4\pi^{2} }{g})x^{2}\\   0=(\frac{4\pi^{2}  }{g} )x^{2}-(T^{2} )x+(\frac{\pi^{2}L^{2}   }{3g} )\\ 4.03x^{2}-23.04x+0.335=0

After Solving this quadratic we get

x₁=5.702 m

x₂=0.01457 m

One of the solution is an impossible value for x (x=5.70m is greater than L)

So we choose the other one

x=0.01457 m

3 0
4 years ago
A rocket is launched upward with a constant acceleration of 165 m/s^2. After 8.00 seconds of ascension a passenger on the rocket
Novay_Z [31]

To solve this problem we will apply the concepts related to the linear kinematic movement. We will start by finding the speed of the body from time and the acceleration given.

Through the position equations we will calculate the distance traveled.

Finally, using this same position relationship and considering the previously found speed, we can determine the time to reach your goal.

For time (t) and acceleration (a) we have to,

t = 8s, a = 165m/s^2

The velocity would be,

u = a*t \\u = 165*8\\u = 1320m/s

Now the position is,

h= \frac{1}{2} at^2

h = \frac{1}{2} 165*8^2

h = 5280m

Now with the initial speed and position found we will have the time is,

h=ut +\frac{1}{2} at^2

-5280=1320t - \frac{1}{2} 9.8t^2

4.9t^2-1320t-5280=0

Solving the polynomian we have,

t = 273.33s = 4.56minutes

Therefore  the rocket will take to hit the ground around to 4.56min

5 0
3 years ago
A 120-kg hollow spherical ball 1 m in diameter accelerates at a constant rate from rest to 5 rpm in 20 s and then continues to r
FromTheMoon [43]

Answer:

Explanation:

a )

moment of inertia of hollow ball

= 2 / 3  mR²  , m is mass and R is radius of the ball

= 2 / 3 x 120 x .5²

= 20 kg m²

b )

5 rpm =      5 / 60 rps

n = .0833

angular velocity ω = 2πn= 2 x 3.14 x .0833=  .523 rad /s

angular acceleration = increase in angular velocity / time

= .523 - 0 / 20

α = .02615 rad /s²

c )

Torque = moment of inertia x angular acceleration

= 20 x .02615

= .523 Nm

d )

θ = 1/2 α t²

= .5 x  .02615 x 20²

= 5.23

2π n = 5.23 where n is required number

n = .83

3 0
3 years ago
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