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3 years ago

9

What is a moment of a force

1 answer:

kirza4 [7]3 years ago

7 0

Answer:

In physics and mechanics, torque is the rotational equivalent of linear force. It is also referred to as the moment, moment of force, rotational force or turning effect, depending on the field of study. The concept originated with the studies by Archimedes of the usage of levers

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A car goes from 80 km/h to 20 km/h in 0.5 h. What is the acceleration in km/h2?

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The answer is attached below.
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4 years ago

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An outside force, Fo, brings two small metal spheres, A and B, at rest from a long distance away to a point where they are 1 met

Ksenya-84 [330]

Answer:

1)

The total work done by outside force is $W_{o}=0.294J$

2)

The total work done by the electric field is $-W_{o} =-0.294J$

3)

The potential energy of the two sphere system is $PE = W_{o} = 0.294J$

4)

The magnitude of the acceleration of sphere A is $a_{A} = 66.868m/s^2$

5)

The magnitude of the acceleration of sphere B is $a_{B} = 26.747 \ m/s^2$

6)

The magnitude of velocity sphere A after a very long time is $v_{A} = 10.251 \ m/s$ \

7) The magnitude of velocity sphere B after a very long time is $v_{B} = 4.1 m/s$

Explanation:

The explanation is shown on the first and second uploaded image

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3 years ago

Which phase comes after waxing crescent moon

12345 [234]

Answer:

new moon

Explanation:

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3 years ago

1. A baseball is thrown vertically at 16.7 m/s. What is the maimum height of the baseball?

Anvisha [2.4K]

Answer:

14.2 m

Explanation:

Using conservation of energy:

PE at top = KE at bottom

mgh = ½ mv²

h = v² / (2g)

h = (16.7 m/s)² / (2 × 9.8 m/s²)

h = 14.2 m

Using kinematics:

Given:

v₀ = 16.7 m/s

v = 0 m/s

a = -9.8 m/s²

Find: Δy

v² = v₀² + 2aΔy

(0 m/s)² = (16.7 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 14.2 m

7 0

4 years ago

A satellite is put into an orbit at a distance from the center of the Earth equal to twice the distance from the center of the E

Sveta_85 [38]

Answer:

995 N

Explanation:

Weight of surface, w= 4000N

Gravitational constant, g, is taken as 9.81 hence mass, m of surface is W/g where W is weight of surface

m= 4000/9.81= 407.7472

Using radius of orbit of 6371km

The force of gravity of satellite in its orbit, $F=\frac {GMm}{(2r)^{2}}=\frac {GMm}{4(r)^{2}}$

Where $G=6.67*10^{-11}$ and $M=5.94*10^{24}$

$F=\frac {(6.67*10^{-11}*5.94*10^{24}*407.7472)}{4*({6.371*10^{6}m)}^{2}}$

F= 995.01142 then rounded off

F=995N

6 0

3 years ago