False because the allocation rule of "first come-first served" promotes productive cooperation.
Explanation:
The runner was 8.6km away from the finish line when the bird starts flying.
Therefore it takes the bird 8.6/14.4 = 0.60 hours for the bird to fly to the finish line.
In that 0.60 hours, the runner would have ran an extra 3.6km/h * 0.6h = 2.16km.
Now, the runner and the bird are flying towards each other. The distance between them is 8.6 - 2.16 = 6.44km and their combined speed is 18.0km.
Hence, they will meet in 6.44/18.0 = 0.36 hours.
Overall, the bird flew for 0.60 + 0.36 = 0.96 hours, and flew 14.4km/h * 0.96h = 13.8km.
Answer:
8 Hz, 48 Hz
Explanation:
The standing waves on a string (or inside a pipe, for instance) have different modes of vibrations, depending on how many segments of the string are vibrating.
The fundamental frequency of a standing wave is the frequency of the fundamental mode of vibration; then, the higher modes of vibration are called harmonics. The frequency of the n-th harmonic is given by

where
is the fundamental frequency
In this problem, we know that the wave's third harmonic has a frequency of

This means this is the frequency for n = 3. Therefore, we can find the fundamental frequency as:

Now we can also find the frequency of the 6-th harmonic using n = 6:

It becomes a isotope if an atom were to lose or gain a neutron.
Answer:
u_o = 12.91 m/s
Explanation:
Given:
- mass of the ball m = 0.15 kg
- Spacing between each equipotential line s = 1.0 m
- Charge on the ball is q = 10 mC
Find:
- What initial velocity must it have at the 200-V level for it to reach its maximum height at the 700-V level
Solution:
- Notice that the Electric field lines are directed from Higher potential to lower potential i.e V = + 700 level to V = 200 level. The gravitational acceleration also acts downwards.
- We will compute a resultant acceleration due to gravity and Electric Field as follows:
g' = g + F_e / m
- Where F_e is the Electrostatic Force given by:
F_e = E*q
- Electric field strength is given by:
E = V / d
- Hence,
g' = g + (dV*q/ d*m)
- Input values:
g' = 10 + (500*10^-2 / 5*0.15)
g' = 16.6667 m/s^2
- Now use one of the equation of motions in y-direction:
h_max = u_o ^2 / 2*g'
- Input values where h_max = 5 m
5*2*g' = u_o ^2
u_o = sqrt (166.667)
u_o = 12.91 m/s