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victus00 [196]
3 years ago
10

Explain why the extrapolated temperature is used to determine the maximun temperature of the mixture rather than the highest rec

orded temperature
Physics
2 answers:
Oksi-84 [34.3K]3 years ago
6 0
The extrapolated temperature is used to define the maximum temperature of the mixture relatively than the highest recorded temperature in which the conclusion will effect in a higher specific heat value. Heat is bound to escape from whatever apparatus is using, therefore it is needed to account for the loss of the heat that does not go into increasing the temperature of the mixture. 
Verizon [17]3 years ago
5 0

<u><em>The extrapolated temperature is used to determine the maximum temperature of mixture so that the amount of heat released by the mixture into the surroundings is settled and accurate reading is measured. </em></u>

<u><em> </em></u>

Further Explanation:

When a mixture is heated to a particular temperature, the amount of energy provided to the mixture suddenly appears to increase the temperature of the whole mixture to a certain value instantly.

But this temperature is not the correct reading for the maximum temperature of the mixture because, the amount of heat supplied t the mixture slowly reaches its equilibrium by heating its surroundings and the air around it.

Some of the heat may get dissipated in heating the apparatus because the surroundings of the mixture are not ideal. Therefore, the equilibrium temperature of the mixture may fall to some value. That’s why the maximum recorded temperature is not considered the maximum temperature of the mixture.

Thus, <u><em>the extrapolated temperature is used to determine the maximum temperature of mixture so that the amount of heat released by the mixture into the surroundings is settled and accurate reading is measured. </em></u>

Learn More:

1. To find the number of neutrons in an atom you would subtract <u>brainly.com/question/1983390 </u>

2. Calculate the density of a sample of gas with a mass of 30 g and volume of 7500 cm3 <u>brainly.com/question/898149 </u>

3. According to Charles’s law, for a fixed quantity of gas at constant pressure <u>brainly.com/question/7316997 </u>

Answer Details:

Grade: High School

Subject: Physics

Chapter: Heat and Temperature

Keywords:

Extrapolated temperature, maximum temperature, highest recorded temperature, surroundings, heat loss, apparatus, ideal, equilibrium temperature.

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Energy is conventionally measured in Calories as well as in joules. One Calorie in nutrition is one kilocalorie, defined as 1 kc
Sergeeva-Olga [200]

Answer:

a) The student must run flight of stairs to lose 1.00 kg of fat 709.5 times.

b) Average power

P(w)= 1062.07 [w]

P(hp)=1.42 [hp]

c) This activity is highly unpractical, because the high amount of repetitions he has to due in order to lose, just 1 Kg of fat.

Explanation:

First, lets consider the required amount of work to move the mass of the student. (considering running stairs just as a vertical movement)

Work:

W= F*d= m*g*d

Where m is the mass of the student, g is gravity (9.8 m/s) and d is the total distance going up the stairs (0.15m *85steps= 12.75m )

W= F*d= m*g*d=85* 9.8*12.75=10620.75 [J]

Converting from Joules to Kcals:

\frac{10620.75}{4186} =2.537 Kcal

Now lets take into account the efficiency of the human body (20%)

2.537 ---> 20%

 x       ---> 100%

x=\frac{2.537*100}{20} =12.685

So the student is consuming 12.685 KCals each time he runs up the stairs.

Now,

1 g --> 9 Kcals

1000 g --> 9000KCals

Burning 1 g of fat, requieres 9 KCals, 1000g burns 9000KCals. So in order to burn a 1Kg of fat:

\frac{9000Kcals}{12.685Kcals} =709.5 times

He must run up the stairs 709.5 times, to burn 1 Kg of fat.

********************

For b) just converting units, taking into account the time lapse. (53103.75 is the 100% of the energy in joules, from converting 12.685Kcals to joules)

Power=\frac{Joules}{Seconds} =\frac{53103.75}{50} =1062.075 [W]\\

P(hp)=\frac{P(w)}{745.7} =\frac{1062.075}{745.7} =1.42[hp]

*****

4 0
3 years ago
A hiker walks 11 km due north from camp and then turns and walks 11 km due east. What is the magnitude of the displacement (on a
sattari [20]

Answer:

16 km

Explanation:

Drawing a right triangle to model the problem helps. I started by drawing the lines of the triangle to model the hiker's journey- a vertical straight line for 11 km north and then a horizontal line connected to the top of it for 11 km east; I then drew the hypothenuse to connect the two lines.

The hypothenuse is what we have to solve for, so we will use the Pythagorean Theorem, a^2 + b^2 = c^2. Since both distances are 11 km both a and b in the equation are 11.

11^2 + 11^2 = c^2

121 + 121 = c^2

242 = c^2

c = 15.56

Rounding the answer makes it 16 km for the hiker's magnitude of displacement.

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GalinKa [24]
It IS <span>PE = (1200 kg)(9.8 m/s²)(42 m) = 493,920 J </span>
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