A DVD drive is spinning at 100.0 rpm. A dime (2.00 gm) is placed 3.00 cm from the center of the DVD. What must the coefficient o
1 answer:
Answer:
0.3375
Explanation:
w = angular speed of the DVD drive = 100.0 rpm = =
m = mass of the dime = 2 g = 0.002 kg
r = radius = 3 cm = 0.03 m
μ = Coefficient of friction
The frictional force provides the necessary centripetal force to move in circle. hence
frictional force = centripetal force
μ mg = m r w²
μ g = r w²
μ (9.8) = (0.03) (10.5)²
μ = 0.3375
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Answer:
a) The strength of gravity decreases if one moved away from Jupiter
b) The strength of gravity increases if one fell into Jupiter
Explanation:
The gravitational attraction is given by Newton law of gravitation as follows;
Where;
G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³/(kg·s²)
M = The mass of Jupiter
m = The mass of the nearby body
R = The distance between the centers of Jupiter and the body
From the equation, we have that the gravitational strength varies inversely with the square of the separation distance between two bodies
Therefore, as one moves away, R increases, and the strength of gravity reduces
Similarly as the body falls into Jupiter, R, reduces the gravitational strength increases.