Inertia is what keeps everything moving, so if it didn't exist, the balls wouldn't keep going when they are kicked, or thrown.
Answer:
B can take 0.64 sec for the longest nap .
Explanation:
Given that,
Total distance = 350 m
Acceleration of A = 1.6 m/s²
Distance = 30 m
Acceleration of B = 2.0 m/s²
We need to calculate the time for A
Using equation of motion
![s=ut+\dfrac{1}{2}at_{A}^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat_%7BA%7D%5E2)
Put the value in the equation
![30=0+\dfrac{1}{2}\times1.6\times t_{A}^2](https://tex.z-dn.net/?f=30%3D0%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes1.6%5Ctimes%20t_%7BA%7D%5E2)
![t_{A}=\sqrt{\dfrac{30\times2}{1.6}}](https://tex.z-dn.net/?f=t_%7BA%7D%3D%5Csqrt%7B%5Cdfrac%7B30%5Ctimes2%7D%7B1.6%7D%7D)
![t_{A}=6.12\ sec](https://tex.z-dn.net/?f=t_%7BA%7D%3D6.12%5C%20sec)
We need to calculate the time for B
Using equation of motion
Put the value in the equation
![30=0+\dfrac{1}{2}\times2.0\times t_{B}^2](https://tex.z-dn.net/?f=30%3D0%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes2.0%5Ctimes%20t_%7BB%7D%5E2)
![t_{B}=\sqrt{\dfrac{30\times2}{2.0}}](https://tex.z-dn.net/?f=t_%7BB%7D%3D%5Csqrt%7B%5Cdfrac%7B30%5Ctimes2%7D%7B2.0%7D%7D)
![t_{B}=5.48\ sec](https://tex.z-dn.net/?f=t_%7BB%7D%3D5.48%5C%20sec)
We need to calculate the time for longest nap
Using formula for difference of time
![t'=t_{A}-t_{B}](https://tex.z-dn.net/?f=t%27%3Dt_%7BA%7D-t_%7BB%7D)
![t'=6.12-5.48](https://tex.z-dn.net/?f=t%27%3D6.12-5.48)
![t'=0.64\ s](https://tex.z-dn.net/?f=t%27%3D0.64%5C%20s)
Hence, B can take 0.64 sec for the longest nap .
The temperature of the lithosphere is around 300<span>°C</span> - 500<span>°<span>C</span></span>
Freezing point of the water is known as 273 K
Hope this helps!
Answer:
Explanation:
The law of conservation of mass states that the mass of the elements at the beginning of the reaction(reactants) will equal the mass at the end of the reaction (product) .
In the chemical equation above,the total mass of the reactants is 80g(16+64) and the total mass of the products is also 80g(44+36).therefore the mass remained constant and that's how the equation represents the law of conservation of mass