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Artyom0805 [142]
3 years ago
13

What is types of motion ​

Physics
2 answers:
zlopas [31]3 years ago
8 0

Answer: here the answer!

Explanation:

kotykmax [81]3 years ago
6 0

In the world of mechanics, there are four basic types of motion. These four are rotary, oscillating, linear and reciprocating. Each one moves in a slightly different way and each type of achieved using different mechanical means that help us understand linear motion and motion control.

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Which wave, A or B, has higher energy?
eduard

Answer:

Wave A.

Explanation:

The energy of a wave is directly proportional to the square of the amplitude.

If a wave has higher amplitude, it will have more energy. On the other hand, a wave having lower amplitude, it will have less eenergy.

In this case, we need to tell which wave has higher energy. Hence, the correct option is A because it has a higher amplitude.

8 0
2 years ago
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A plane traveled west for 4.0 hours and covered a distance of 4,400 meters what’s the velocity
tatuchka [14]

0.31m/s

Explanation:

Given parameters:

Time of travel = 4hrs = 4 x 60 x 60 = 14400s

Displacement  = 4400m due west

Unknown:

Velocity = ?

Solution:

Velocity is defined as the displacement  per unit of time. It is expressed in m/s or km/hr:

     Velocity =  \frac{displacement}{time}

     Velocity =   \frac{4400}{14400} = 0.31m/s

Learn more:

Velocity brainly.com/question/10883914

#learnwithBrainly

8 0
3 years ago
Plz help!!!!! Due tomorrow Analyze the weather map in 2 to 3 complete sentences. Describe what the weather will be in Olympia, W
lana66690 [7]

Answer:

Very sorry if this is late

Explanation:

Currently, in Olympia, Washington, it is raining because a cold front with high pressure has met an area with low pressure. This occurs due to the fact that storms are caused by sudden differences in air pressure.

8 0
2 years ago
The tension in the horizontal towrope pulling a water-skier is 250 N while the skier moves due west a distance of 50 m. How much
icang [17]

Answer:

W = 250(50) = 12500 J

Explanation:

5 0
3 years ago
a ballistic pendulum is used to measure the speed of high-speed projectiles. A 6 g bullet A is fired into a 1 kg wood block B su
Galina-37 [17]

Answer:

(a) v-bullet = 399.04 m/s

(b) I = 2.38 kg m/s

(c) T = 2.59 N

Explanation:

(a) To calculate the initial speed of the bullet, you first take into account that the kinetic energy of both wood block and bullet, just after the bullet impacts the block, is equal to the potential gravitational energy of block and bullet when the cord is at 60° respect to the vertical.

The potential energy is given by:

U=(M+m)gh       (1)

U: potential energy

M: mass of the wood block = 1 kg

m: mass of the bullet = 6g = 6.0*10^-3 kg

g: gravitational constant = 9.8m/s^2

h: distance to the ground

The distance to the ground is calculate d by using the information about the length of the cord and the degrees of the cord respect to the vertical:

h=l-lsin\theta\\\\h=2.2m-2,2m\ sin60\°=0.29m

The potential energy is:

U=(1kg+6*10^{-3}kg)(9.8m/s^2)(0.29m)=2.85J

Next, the potential energy is equal to kinetic energy of the block and the bullet at the beginning of its motion:

U=\frac{1}{2}(M+m)v^2\\\\v=\sqrt{2\frac{U}{M+m}}=\sqrt{2\frac{2.85J}{1kg+6*10^{-3}kg}}=2.38\frac{m}{s}

Next, you use the momentum conservation law, in order to calculate the speed of the bullet before the impact:

Mv_1+mv_2=(M+m)v    (2)

v1: initial velocity of the wood block = 0m/s

v2: initial speed of the bullet

v: speed of bullet and block = 2.38m/s

You solve the equation (2) for v2:

M(0)+mv_2=(M+m)v    

v_2=\frac{M+m}{m}v=\frac{1kg+6*10^{-3}kg}{6*10^{-3}kg}(2.38m/s)\\\\v_2=399.04\frac{m}{s}

The speed of the bullet before the impact with the wood block is 399.04 m/s

(b) The impulse is gibe by the change in the velocity of the block, multiplied by the mass of the block:

I=M\Delta v=M(v-v_1)=(1kg)(2.38m/s-0m/s)=2.38kg\frac{m}{s}

The impulse is 2.38 kgm/s

(c) The force on the cord after the impact is equal to the centripetal force over the block and bullet. That is:

T=F_c=(M+m)\frac{v^2}{l}=(1.006kg)\frac{(2.38m/s)^2}{2.2m}=2.59N    

The force on the cord after the impact is 2.59N

4 0
3 years ago
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