Answer:
n = 10 beats
Explanation:
Given:
- Frequency of note f1 = 151 Hz
- Frequency of note f2 = 155 Hz
- The total time they ring t = 2.5 s
Find:
How many beats are heard
Solution:
- The frequency of beat (fb) is the difference between the two frequencies of notes as follows:
fb = f2 - f1
fb = 155 - 151
fb = 4 Hz
- The number of beats per second is also called beat frequency:
n = fb*t
n = 4*2.5
n = 10 beats
Answer:
d. No, porque la ecuación de trabajo lo define.
Explanation:
En Física, el trabajo realizado se puede definir como la cantidad de energía transferida cuando un objeto o cuerpo se mueve a lo largo de una distancia debido a la acción de una fuerza externa.
Matemáticamente, el trabajo realizado viene dado por la fórmula;
<u>Dónde;</u>
- W es el trabajo realizado.
- F representa la fuerza que actúa sobre un cuerpo.
- d representa la distancia recorrida por el cuerpo.
Por lo tanto, podemos deducir de la definición de trabajo y su fórmula que el trabajo se realiza cuando un objeto (cuerpo) se mueve una distancia o experimenta cualquier forma de desplazamiento mientras transfiere energía.
Answer:
ac = 124.6 m/s²
Explanation:
When an object executes a uniform circular motion, acceleration is produced in it due to a change in its direction during the motion. This acceleration is called the centripetal acceleration. The formula used to find this acceleration is given as follows:

where,
ac = centripetal acceleration = ?
v = speed = 9 m/s
r = radius = 0.65 m
Therefore,

<u>ac = 124.6 m/s²</u>
Answer:
d. may be either greater, smaller, or equal to that observed inside the bus.
Explanation:
- The bus is moving at a constant speed. The ball tossed and received by the ball is inside the bus at a speed equal to the speed of the ball. Therefore the speed of the bus becomes zero with respect to the observer inside the bus.
- Now the observer inside the bus noticed the ball from the inside of the bus, so he threw the ball back and forth from the ball with the speed v relative to the observer.
- Now the observer outside the bus could see the bus moving at speed relative to its reference point and also throwing the ball from front to back. The speed of the ball to the observer outside the bus The speed of the bus to the observer outside the bus is minus the speed of the ball to the observer inside the bus.
- Therefore, the ball speed = (u-v) relative to the observer outside the bus.
Answer:it is the exact location of something.
Explanation: