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hram777 [196]
3 years ago
9

65. A length of wire is bent into a closed loop and a magnet is plunged into it, inducing a voltage and, consequently, a current

in the wire. A second length of wire, twice as long, is bent into two loops of wire, and a magnet is similarly plunged into it. Twice the voltage is induced, but the current is the same as that produced in the single loop. Why
Physics
2 answers:
natulia [17]3 years ago
6 0

Answer:

Resistance of the second wire is twice the first wire.

Explanation:

Let us first see the formula of resistance;

R = pxL/A

Here L is the lenght of the wire, A the area and p is the resistivity of wire.

As we are given that the length of second wire is double than that of the first wire, hence the resistance of second wire would be double.

Since we have two loop in second case, inducing double voltage but as resistance is doubled so the current would remain same according to ohms law

I = V/R

OLga [1]3 years ago
6 0

Answer:

The resistance of the second wire is two times that of the first wire. Even though the voltage doubles, current still remain the same.

Explanation:

The voltage induced is directly proportional to the number of loops of the wire. Resistance is directly proportional to the length of the wire as long as all other parametersare constant in the formula R=PL/A. The second wire has twice the length and twice the number of turns than the first wire.

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Alex Ar [27]

Answer: When a liquid or gas is heated, the molecules move faster, bump into each other, and spread apart. Because the molecules are spread apart, they take up more space. ... The molecules move more slowly and take up less space. Therefore temperature can affect density.

Explanation:

3 0
3 years ago
¿Qué distancia recorre un móvil que lleva una aceleración de 5m/s durante 10seg?
coldgirl [10]

Answer:

250 m

Explanation:

The car in this problem is moving of uniform accelerated motion, so we can use the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

Assuming the car starts from rest,

u = 0

Also we know that

a = 5 m/s^2 (acceleration of the car)

t = 10 s

Substituting, we find the distance covered:

s=0+\frac{1}{2}(5)(10)^2=250 m

3 0
3 years ago
How much energy is transferred in 10 seconds with a current of 13 amperes and a potential difference of 230 volts?​
Serhud [2]

29900 J

Explanation:

Recall that

P = VI

= (230 volts)(13 A)

= 2990 watts

Also,

E = Pt

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5 0
2 years ago
what is the acceleration of a car that slows down from 60m/s to 40 m/s during a period of 10 seconds?
algol [13]

The acceleration of the car is stated as -2 m/s², while the deceleration of the car is termed as 2 m/s².

Answer:

Explanation:

Acceleration exerted by any object in order of decrease in the speed is termed as deceleration. In other words , negative acceleration or acceleration acting in opposite direction to stop the motion of any object is termed as deceleration. The magnitude of acceleration and deceleration is same only the direction is completely opposite to each other. So the negative sign will be obtained for acceleration value of any object whose velocity slows down from initial velocity.

Here , the initial velocity was 60 m/s and the final velocity is slowed down to 40 m/s in time 10 s.

So acceleration = (Final velocity - Initial velocty)/Time

Acceleration = (40-60)/10 = -20/10 = -2 m/s².

Thus, the acceleration of the car is stated as -2 m/s², while the deceleration of the car is termed as 2 m/s².

5 0
3 years ago
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