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dmitriy555 [2]
3 years ago
9

We now have an algebraic expression with only one variable, which can be solved. Once we have that, we can plug it back into one

of the original equations (or the expression derived in Part A) to solve for the other variable. When this is done with the system of two equations from Parts A and B, what is the solution?

Physics
1 answer:
Len [333]3 years ago
3 0

Answer:

A=1

B=-2

Explanation:

Part A and B of the question wasn't given, however, I attached the relevant parts to solve this question as follows.

From part B as attached, it shows that the right option is C which is

2A+3B=-4

Substituting B with 3A-5 then we form the second equation as shown

2A+3(3A-5)=-4

By simplifying the above equation, we obtain

2A+9A-15=-4

Re-arranging, then

11A=-4+15

Finally

11A=11

A=1

To obtain B, we already know that 3A-5 so substituting the value of A into the above then we obtain

B=3(1)-5=-2

Therefore, required values are 1 and -2

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Please help me :Find the resultant of two forces of 1.5N and 2.0N at 90 degrees to each other, with the 1.5N force acting vertic
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Answer:

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Explanation:

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Answer:

Complete Circuit

Explanation:

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An electron and a proton are fixed at a separation distance of 973 nm. Find the magnitude and the direction of the electric fiel
Vilka [71]

Answer:

The magnitude is: |E|=6084.1\: N/C

The direction of E is in the negative x-direction.

Explanation:

The electric field equation is:

E=k\frac{Q}{r^{2}}

Where:

  • Q is the charge (we can choose the electron or the proton)
  • r is the distance (in our case is at the midpoint 973/2 nm)
  • k is the Coulomb constant (9*10^{9}\: Nm^{2}C^{-2})

Using the electron charge (e = -1.6*10^{-19}\: C)

E=-9*10^{9}\frac{1.6*10^{-19}}{(486.5*10^{-9})^{2}}

The magnitude is:

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The direction of E is in the negative x-direction.

I hope it helps you!

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