We now have an algebraic expression with only one variable, which can be solved. Once we have that, we can plug it back into one
of the original equations (or the expression derived in Part A) to solve for the other variable. When this is done with the system of two equations from Parts A and B, what is the solution?
1 answer:
Answer:
A=1
B=-2
Explanation:
Part A and B of the question wasn't given, however, I attached the relevant parts to solve this question as follows.
From part B as attached, it shows that the right option is C which is
2A+3B=-4
Substituting B with 3A-5 then we form the second equation as shown
2A+3(3A-5)=-4
By simplifying the above equation, we obtain
2A+9A-15=-4
Re-arranging, then
11A=-4+15
Finally
11A=11
A=1
To obtain B, we already know that 3A-5 so substituting the value of A into the above then we obtain
B=3(1)-5=-2
Therefore, required values are 1 and -2
You might be interested in
Answer:
GPE = 388.08 Joules.
Explanation:
Given the following data;
Mass = 0.550kg
Speed = 335 m/s
Height = 72 meters
We know that acceleration due to gravity, g is equal to 9.8 m/s²
To find the gravitational potential energy;
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;
Where;
G.P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Substituting into the formula, we have;
GPE = 388.08 Joules.
Answer:5
Explanation:
Given
speed of object
radius of circle
Force towards the center
Work done is given by the dot product of Force and displacement
and we know know displacement of the object is along the circle which is perpendicular to the force acting therefore Work done will be zero
Answer:
a) 2.43 m/s
b) 4.83 m/s
c) 0.023 m/s²
Explanation:
a) Both cars cover a distance of 510 m in 210 s. Since car A has no acceleration
Speed = Distance / Time
Velocity of car A is 2.43 m/s
t = Time taken = 210 seconds
u = Initial velocity
v = Final velocity
s = Displacement = 510 m
a = Acceleration
c)
Acceleration of car B is 0.023 m/s²
b)
Final velocity of car B is 4.83 m/s